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alisha [4.7K]
4 years ago
7

About 13 out of 20 homes have a personal computer. On a street with 60 homes, how many would you expect to have a personal compu

ter?
Mathematics
2 answers:
Aleks04 [339]4 years ago
5 0
This can be solved using a ratio. The ratio is: 13/20=x/60 this would then become 20x= 780  divide both sides by 20 and you get x=39. the answer is 39
Mashutka [201]4 years ago
3 0
It can go in a more simple way.

20 goes into 60 3 times, this 3 being the multiplier.

13 x 3 = 39
_
20 x 3 = 60

39:60 homes on a street with 60 homes have personal computers.
:D
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What is 153/4 as a whole number
maw [93]

\frac{4}{3}  =  \frac{51}{n} \\  =  >  \frac{3}{4}   =  \frac{n}{51 }  \\  =  > n =  \frac{3}{4}  \times 51 \\  =  > n =  \frac{153}{4}  \\  =  > n = 38 \frac{1}{4}

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0
2 years ago
Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants
lozanna [386]

Answer:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

Step-by-step explanation:

You have the following differential equation:

3y''+12y=0     (1)

In order to find the solution to the equation, you can use the method of the characteristic polynomial.

The characteristic polynomial of the given differential equation is:

3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i

The solution of the differential equation is:

y(x)=c_1e^{m_1x}+c_2e^{m_2x}   (2)

where m1 and m2 are the roots of the characteristic polynomial.

You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

4 0
3 years ago
What is the correct answer please I need help.
vfiekz [6]

Answer:

D: What is the height of the tallest player on a team.

Step-by-step explanation:

8 0
3 years ago
Match each expression written in standard form to the equivalent expression in factored form
den301095 [7]

Answer:

1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)

4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)

Step-by-step explanation:

To obtain the answer to the question, first let us factorise each expression. This is illustrated below:

1. 15x^7y^2 + 4x^3

Common factor is x^3, therefore the expression is written as:

x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x

Common factor is 3x, therefore the expression is written as:

3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy

Common factor is 3xy, therefore the expression is written as:

3xy(5x^6y + 2)

4. 15x^7 + 10y^2

Common factor is 5, therefore the expression can be written as:

5(3x^7 + 2y^2)

4 0
3 years ago
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ahrayia [7]

Answer:

Step-by-step explanation:

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8 0
3 years ago
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