By "slope" I assume you mean slope of the tangent line to the parabola.
For any given value of <em>x</em>, the slope of the tangent to the parabola is equal to the derivative of <em>y</em> :

The slope at <em>x</em> = 1 is 5:

The slope at <em>x</em> = -1 is -11:

We can already solve for <em>a</em> and <em>b</em> :


Finally, the parabola passes through the point (2, 18); that is, the quadratic takes on a value of 18 when <em>x</em> = 2:

So the parabola has equation

9514 1404 393
Answer:
(b) T(x, y) -> (x-3, y-6)
Step-by-step explanation:
Each image point is 3 left and 6 down from the corresponding pre-image point. That is -3 is added to each x-value, and -6 is added to each y-value. That transformation is represented by ...
T(x, y) ⇒ (x-3, y-6)
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