By angular speed, the frequency is 2.39 Hz.
We need to know about the angular speed of harmonic oscillation. the angular speed can be determined as
ω² = k / m
where ω is angular speed, k is spring constant, and m is the mass.
The angular speed can be calculated by
ω = 2πf
Hence,
ω² = k / m
(2πf)² = k / m
k = (2πf)² / m
where f is frequency.
From the question above, we know that:
m1 = 0.6 kg
f1 = 3 Hz
m2 = 0.38 kg
The spring is same, hence the spring constant is the same
k1 = k2
(2πf1)² / m1 = (2πf2)² / m2
f1² / m1 = f2² / m2
3² / 0.6 = f2² / 0.38
f2² = 5.7
f2 = 2.39 Hz
Find more on angular speed at: brainly.com/question/6860269
#SPJ4
