Explanation:
The given data is as follows.
= 0, = 0, = 0
= 17.0 m, = 2.10 sec
As the force P is constant and the mass "m" of the tool is constant then it means that the acceleration "a" will also be constant.
Now,
=
17.0 = 2.205a
a =
Also, we know that
F =
m =
So, m =
= 1.66 kg
Since, the tool is subject to its weight W and is in free fall. Hence,
10.0 m =
g = 2.411
Hence, weight of tool in Newtonia is as follows.
W = mg
=
= 4.00 N
Hence, weight of the tool on Newtonia is 4.00 N.
And, weight of the tool on the Earth is as follows.
W =
= 23.62 N
Hence, weight of the tool on Earth is 23.62 N.
Answer:
Because the bullet is smaller and has a sharp/pointy tip.
Explanation:
The bullet kinda puts the majority of kinetic energy in a small are, whereas the gun butt kinda spreads the energy evenly amongst a larger surface. If more explanation is needed add comment.
Answer:
300J
The total work done or energy transferred is equal to the product of the force and the displacement in the direction of the force applied.
In this case it would be
300N x 10m to get 3000J.
This energy is transferred in 10 seconds and since power is energy transferred per unit time.
3000J ÷ 10 = 300 Watts or 300 Joules per second.
so your answer is 300 W
Answer:
a = -47.93 m/s²
Explanation:
given,
speed of particle in positive x-direction, u = 97 m/s
speed of particle in opposite direction, v = -42 m/s
time = 2.9 s
average acceleration, a = ?
now,
a = -47.93 m/s²
Hence, the average acceleration is equal to -47.93 m/s²
The power is defined as the work done (W) by the transmission per unit of time (t) to accelerate the train:
To find the work done, we can use the work-energy theorem, which states that the work done is equal to the variation of kinetic energy of the train. Since the trains starts from rest, its initial kinetic energy is zero, so the work done is simply equal to the final kinetic energy:
where m is the mass of the train and
is its final velocity.
The mass of the train is m=0.875 kg while its final velocity is
, the work done by the electrical transmission is
And since this work is done in a time of t=20.5 ms=0.0205 s, the minimum power delivered is