The electric motor of a model train accelerates the train from rest to 0.665 m/s in 20.5 ms. the total mass of the train is 875
1 answer:
The power is defined as the work done (W) by the transmission per unit of time (t) to accelerate the train:
To find the work done, we can use the work-energy theorem, which states that the work done is equal to the variation of kinetic energy of the train. Since the trains starts from rest, its initial kinetic energy is zero, so the work done is simply equal to the final kinetic energy:
where m is the mass of the train and
is its final velocity.
The mass of the train is m=0.875 kg while its final velocity is
, the work done by the electrical transmission is
And since this work is done in a time of t=20.5 ms=0.0205 s, the minimum power delivered is
To find the work done, we can use the work-energy theorem, which states that the work done is equal to the variation of kinetic energy of the train. Since the trains starts from rest, its initial kinetic energy is zero, so the work done is simply equal to the final kinetic energy:
where m is the mass of the train and
The mass of the train is m=0.875 kg while its final velocity is
And since this work is done in a time of t=20.5 ms=0.0205 s, the minimum power delivered is
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