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2 years ago

What is true of all places on earth during the equinoxes

Physics

2 answers:

tia_tia [17]2 years ago

6 0

Answer:There is approximately equal length of night and day in all places of the earth during equinoxes.

Explanation: At some point in the earth's revolution around the sun, it's observed that the earth's axis doesn't tilt towards nor away from the sun.

So this results to nearly equal amount of darkness and daylight across the earth. This happens just twice in a year around March 20-21 and September 22-23.

taurus [48]2 years ago

4 0

Answer:

The length and duration of the day time and the length and duration of the night time are the same all over the planet.

Explanation:

Equinox is known as the period of time when the plane of Earth's equator passes through the center of the Sun. This occurs twice each year.

it is the moment at which the center of the visible Sun is directly above the equator.

At Equinox, the daytime and nighttime are of approximately equal duration all over the planet. Although, They are not totally and exactly equal.

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Having aced your Physics 2111 class, you get a sweet summer-job working in the International Space Station. Your room-mate, Cosm

Sphinxa [80]

Answer:

The speed is $s = 5.857 m/s$

The distance is $D = 22.4 \ m$

Explanation:

From the question we are told that

The speed of the banana is $v = 16 \ m/s$

The distance from my location is $d = 8.2 \ m$

The time taken is $t = 1.4 \ s$

The speed of the ice cream is

$s = \frac{d}{t}$

substituting values

$s = \frac{8.4}{1.4}$

$s = 5.857 m/s$

The distance of separation between i and Valdimir is the same as the distance covered by the banana

$D = v * t$

substituting values

$D = 16 * 1.4$

$D = 22.4 \ m$

3 0

2 years ago

A spring is used to stop a 50-kg package which is moving down a 20º incline. The spring has a constant k = 30 kN/m and is held b

Elina [12.6K]

Answer:

0.3 m

Explanation:

Initially, the package has both gravitational potential energy and kinetic energy. The spring has elastic energy. After the package is brought to rest, all the energy is stored in the spring.

Initial energy = final energy

mgh + ½ mv² + ½ kx₁² = ½ kx₂²

Given:

m = 50 kg

g = 9.8 m/s²

h = 8 sin 20º m

v = 2 m/s

k = 30000 N/m

x₁ = 0.05 m

(50)(9.8)(8 sin 20) + ½ (50)(2)² + ½ (30000)(0.05)² = ½ (30000)x₂²

x₂ ≈ 0.314 m

So the spring is compressed 0.314 m from it's natural length. However, we're asked to find the additional deformation from the original 50mm.

x₂ − x₁

0.314 m − 0.05 m

0.264 m

Rounding to 1 sig-fig, the spring is compressed an additional 0.3 meters.

8 0

2 years ago

One gram of salt in 100 liters of water could be considered a _______________________ solution

Doss [256]

That would be a diluted solution

5 0

3 years ago

Read 2 more answers

How many orders of magnitude (powers of ten) is the distance to the moon greater than the distance across the Atlantic ocean?

kupik [55]

Answer:

The distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

Explanation:

We have the average distance across the Atlantic ocean, $d_i=3700\ mi$

the average distance to the moon, $d_m=238,900\ mi$

The factor by which the distance to moon is greater than the width of Atlantic ocean:

$f=\frac{d_m}{d_i}$

$f=\frac{238,900}{3700}$

$f=64.57$

i.e.

the distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

6 0

2 years ago

Neutron stars are extremely dense objects formed from the remnants of supernova explosions. Many rotate very rapidly. Suppose th

mihalych1998 [28]

Answer:

10989.55932 rad/s

Explanation:

m = Mass of object

M = Mass of neutron star = $2\times 1.989\times 10^{30}\ kg$

R = Radius of neutron star = 13000 m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

$\omega$ = Angular speed

Here, the gravitational force will balance the centripetal force

$\dfrac{GmM}{R^2}=mR\omega^2\\\Rightarrow \omega=\sqrt{\dfrac{GM}{R^3}}\\\Rightarrow \omega=\sqrt{\dfrac{6.67\times 10^{-11}\times 2\times 1.989\times 10^{30}}{13000^3}}\\\Rightarrow \omega=10989.55932\ rad/s$

The greatest possible angular speed an object can have is 10989.55932 rad/s

8 0

3 years ago