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3 years ago

What is true of all places on earth during the equinoxes

Physics

2 answers:

tia_tia [17]3 years ago

6 0

Answer:There is approximately equal length of night and day in all places of the earth during equinoxes.

Explanation: At some point in the earth's revolution around the sun, it's observed that the earth's axis doesn't tilt towards nor away from the sun.

So this results to nearly equal amount of darkness and daylight across the earth. This happens just twice in a year around March 20-21 and September 22-23.

taurus [48]3 years ago

4 0

Answer:

The length and duration of the day time and the length and duration of the night time are the same all over the planet.

Explanation:

Equinox is known as the period of time when the plane of Earth's equator passes through the center of the Sun. This occurs twice each year.

it is the moment at which the center of the visible Sun is directly above the equator.

At Equinox, the daytime and nighttime are of approximately equal duration all over the planet. Although, They are not totally and exactly equal.

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kap26 [50]

S = 10 + (-4) = 6

Displacement is vector quantity

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2 years ago

A pet-store supply truck moves at 25.0 m/s north along a highway. inside, a dog moves at 1.75 m/s at an angle of 35.0Â° east of

koban [17]

<u>Answer:</u>

Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.

<u>Explanation:</u>

Let the east point towards positive X-axis and north point towards positive Y-axis.

Speed of truck = 25 m/s north = 25 j m/s

Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s

= (1.43 i + 1.00 j) m/s

Velocity of the dog relative to the road = 25 j + 1.43 i + 1.00 j = 1.43 i + 26.00 j

Magnitude of velocity = 26.04 m/s

Angle from positive horizontal axis = 86.85⁰

So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.

4 0

3 years ago

Jenny pushes a 40 N crate down the hall 2m. How much work did she do?

Shalnov [3]

Work done = force x distance = 40 x 2 = 80 Joules.

8 0

3 years ago

During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca

Dmitriy789 [7]

Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

g is the acceleration due to the gravity = 9.81 m/s²

Now,

the centripetal acceleration is given as,

$a=\frac{v^2}{r}$

r is the radius of the loop

on substituting the respective values, we get

$8\times9.81=\frac{340^2}{r}$

r = 1472.98 m

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3 years ago

Step 2: Apply NEwton's second law Apply ∑Fy = may , what should ay be equal to, since the block doesn't move in the y direction

andrey2020 [161]

Answer:

∑Fy = 0, because there is no movement, N = m*g*cos (omega)

Explanation:

We can solve this problem with the help of a free body diagram where we show the respective forces in each one of the axes, y & x. The free-body diagram and the equations are in the image attached.

If the product of mass by acceleration is zero, we must clear the normal force of the equation obtained. The acceleration is equal to zero because there is no movement on the Y-axis.

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3 years ago