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maw [93]
2 years ago
12

What is true of all places on earth during the equinoxes

Physics
2 answers:
tia_tia [17]2 years ago
6 0

Answer:There is approximately equal length of night and day in all places of the earth during equinoxes.

Explanation: At some point in the earth's revolution around the sun, it's observed that the earth's axis doesn't tilt towards nor away from the sun.

So this results to nearly equal amount of darkness and daylight across the earth. This happens just twice in a year around March 20-21 and September 22-23.

taurus [48]2 years ago
4 0

Answer:

The length and duration of the day time and the length and duration of the night time are the same all over the planet.

Explanation:

Equinox is known as the period of time when the plane of Earth's equator passes through the center of the Sun. This occurs twice each year.

it is the moment at which the center of the visible Sun is directly above the equator.

At Equinox, the daytime and nighttime are of approximately equal duration all over the planet. Although, They are not totally and exactly equal.

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Vector e is 0.111m long in a 90 deg direction. Vector f is 0.233 m long in 400 deg direction. Find the direction of their vector
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Answer:

50.6

Explanation:

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3 years ago
Match each media portrayal with the type of behavior the media portrayal is
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The hero attending a funeral is safe behavior while the hero driving fast is riskier behavior
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Why is electric current scalar quantity with having direction ?​
frez [133]

Explanation:

It represents the direction of flow of positive charge but is treated as a scalar quantity because current follows the laws of scalar addition and not the laws of vector addition. The angle between the wires carrying current does not affect the total current in the circuit.

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1 year ago
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A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.460 Hz. The pendulum ha
zlopas [31]

Answer:

The  moment of inertia is  I =1.0697 \ kg m^2

Explanation:

From the question we are told that

    The  frequency is  f  =  0.460 \ Hz

    The  mass of the pendulum is  m  =  2.40  \ kg

    The  location of the pivot from the center is d  =  0.380 \ m

     

Generally the period of the simple harmonic motion is mathematically represented as

        T   = 2 \pi  *  \sqrt{  \frac{I}{ m  *  g *  d  } }

Where I is the moment of inertia about the pivot point , so making I the subject of the formula it

=>    I =  [ \frac{T}{2 \pi } ]^2 *  m*  g * d

But the period of this simple harmonic motion can also be represented mathematically as

        T  =  \frac{1}{f}

substituting values

      T  =  \frac{1}{0.460}

      T  =  2.174 \ s

So

      I =  [ \frac{2.174}{2 * 3.142 } ]^2 *   2.40*  9.8 * 0.380

      I =1.0697 \ kg m^2

4 0
2 years ago
A 1500 kg car traveling at 15.0 m/s to the south collides with a 4500 kg truck that is at rest at a stopligt. The car comes to a
Burka [1]

Answer:

5 m/s, moving to the South.

Explanation:

Parameters given:

Mass of car, m = 1500 kg

Initial velocity of car, u = 15 m/s

Mass of truck, M = 4500 kg

Initial velocity of truck, v = 0 m/s (Truck is at rest)

Final velocity of car, U = 0 m/s (Car comes to a stop)

Final velocity of truck = V

Because the collision is elastic, we can apply the principle of conservation of momentum, we have that:

Total initial momentum = Total final momentum

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The velocity carries a positive sign, hence, it's moving in the same direction as the car was moving initially.

That is, it's moving to the South.

8 0
2 years ago
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