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3 years ago

What is true of all places on earth during the equinoxes

Physics

2 answers:

tia_tia [17]3 years ago

6 0

Answer:There is approximately equal length of night and day in all places of the earth during equinoxes.

Explanation: At some point in the earth's revolution around the sun, it's observed that the earth's axis doesn't tilt towards nor away from the sun.

So this results to nearly equal amount of darkness and daylight across the earth. This happens just twice in a year around March 20-21 and September 22-23.

taurus [48]3 years ago

4 0

Answer:

The length and duration of the day time and the length and duration of the night time are the same all over the planet.

Explanation:

Equinox is known as the period of time when the plane of Earth's equator passes through the center of the Sun. This occurs twice each year.

it is the moment at which the center of the visible Sun is directly above the equator.

At Equinox, the daytime and nighttime are of approximately equal duration all over the planet. Although, They are not totally and exactly equal.

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A solid 0.4550 kg ball rolls without slipping down a track toward a vertical loop of radius R = 0.6750 m . What minimum translat

Talja [164]

Answer:

u = 3.35 m/s

Explanation:

given,

mass , m = 0.455 kg

R = 0.675 m

Height of Loop = 1.021 m

the speed required at the top of loop be v

equating the force vertically

$m g =\dfrac{mv^2}{r}$

$9.81 =\dfrac{v^2}{0.675}$

v² = 6.622

v = 2.57 m/s

Let the initial speed of ball be u

using conservation of energy

$\dfrac{1}{2}mu^2 + \dfrac{1}{2}I\omega^2 + m g h = \dfrac{1}{2}I\omega^2 + \dfrac{1}{2}mv^2+ m g (2 R)$

where, $I =\dfrac{2}{5}mr^2$

$\dfrac{1}{2}mu^2 + \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{u}{r})^2 + m g h = \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{v}{r})^2 + \dfrac{1}{2}mv^2+ m g (2 R)$

$0.7 u^2 + g H = 0.7 v^2 + g(2R)$

$0.7 u^2 +9.81 \times 1.021= 0.7\times 2.57^2 + 9.81 \times 2\times 0.675)$

0.7 u² = 7.85092

u² = 11.2156

u = 3.35 m/s

the initial speed is 3.35 m/s

8 0

2 years ago

A 20-kg cart travels at 20 m/s in a circle with a radius of 20 m. What is the centripetal force?

Vlad1618 [11]

Centripetal force = (mass) x (speed)² / (radius)

   = (20 kg) x (20 m/s)² / (20 m)

   = (20 x 20 / 20) (kg-meter/sec²)

   = 20 newtons

5 0

3 years ago

Read 2 more answers

If a car is traveling at an average speed of 60 kilometers per hour, how long does it take to travel 12 kilometers?

Otrada [13]

Answer: 0.2 hour

Explanation:

Speed = Distance / Time

Time = Distance / Speed

= 12/60

= 0.2 hour

8 0

2 years ago

When and where was the worst hurricane in the united states

Andre45 [30]

It was in Texas on September 8, 1900.

8 0

2 years ago

Do you think an observer on another planet in the solar system might see eclipses

artcher [175]

Answer:

Yes

Explanation:

Eclipses: Eclipses are also known as game of shadows where one object comes between the star(light source) and another object in a straight line such that the shadow of one object falls on other object. This can occur when the apparent size of the star and the object is almost same.

Talking about the Earth, the geometry is such that the Moon and the Sun are of same apparent size as seen from the Earth. Thus Lunar and Solar eclipse can be seen from the Earth. If we were to go on any other planet the same phenomenon can be seen provided the apparent size of moon and the Sun from that planet is same.

We have seen and recorded many such eclipses on Jupiter. These are from the perspective of Earth. When the moons of Jupiter comes exactly between the Sun and Jupiter the shadow of moon will fall on Jupiter. The places where the shadow falls, one will see a solar eclipse.

8 0

3 years ago