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maw [93]
3 years ago
12

What is true of all places on earth during the equinoxes

Physics
2 answers:
tia_tia [17]3 years ago
6 0

Answer:There is approximately equal length of night and day in all places of the earth during equinoxes.

Explanation: At some point in the earth's revolution around the sun, it's observed that the earth's axis doesn't tilt towards nor away from the sun.

So this results to nearly equal amount of darkness and daylight across the earth. This happens just twice in a year around March 20-21 and September 22-23.

taurus [48]3 years ago
4 0

Answer:

The length and duration of the day time and the length and duration of the night time are the same all over the planet.

Explanation:

Equinox is known as the period of time when the plane of Earth's equator passes through the center of the Sun. This occurs twice each year.

it is the moment at which the center of the visible Sun is directly above the equator.

At Equinox, the daytime and nighttime are of approximately equal duration all over the planet. Although, They are not totally and exactly equal.

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a generator produces a maximum emf of 240 v when rotating at 3.7 rad/s in a magnetic field of 0.200 t. if the coil has 822 loops
Nesterboy [21]

Answer:

I actually did that but I fprgot

6 0
2 years ago
to move a resting box of 100 Newton on the ground with kinetic friction coeficient of 0,250 is applied a force of 60 N horizonta
krok68 [10]
Work is calculated by multiplying force by the distance that the object had moved. The applied force is 60 N, moving the object by 10 m. Thus, the work does is 600 J. For the friction force which is equal to,
                          100N x 0.250 = 25.0 N
the work done is,
                        W = (60 N - 25 N) x 10 m = 350 J
The kinetic energy of the box can be equated to this force. Thus, the answer is also 350 J. 
6 0
3 years ago
You obtain a 100-W light bulb and a 50-W light bulb. Instead of connecting them in the normal way, you devise a circuit that pla
lesantik [10]

Answer:

When they are connected in series

     The  50 W bulb glow more than the 100 W bulb

Explanation:

From the question we are told that

     The power rating  of the first bulb is P_1  = 100 \ W

      The power rating of the second bulb is  P_2  =  50 \ W

     

Generally the power rating of the first bulb is mathematically represented as

      P_1  =  V^2 R

Where  V is the normal household voltage which is constant for both bulbs

  So  

        R_1  =  \frac{V^2}{P_1 }

substituting values

        R_1  =  \frac{V^2}{100}

Thus the resistance of the second bulb would be evaluated as

       R_2  =  \frac{V^2}{50}

From the above calculation we see that

        R_2  >  R_1

This power rating of the first bulb can also be represented mathematically as  

        P_  1  =  I^2_1  R_1

This power rating of the first bulb can also be represented mathematically as    

       P_  2  =  I^2_2 R_2

Now given that they are connected in series which implies that the same current flow through them so

       I_1^2 =  I_2^2

This means  that

       P \ \alpha  \  R

So  when they are connected in series

     P_2  >  P_1

This means that the 50 W bulb glows more than the 100 \ W bulb

3 0
3 years ago
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Hitman42 [59]
The answer is indeed B
4 0
3 years ago
The question and options are in the photo
inessss [21]

Answer:

Option C

Explanation:

Metal conducts heat much better than wood does.

Since Azam's hand is hotter than room temperature, both the metal and the wood conduct heat away from it.

4 0
3 years ago
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