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adelina 88 [10]
3 years ago
8

Rosa eats a peanut butter sandwich for lunch. Peanut butter contains a lot

Physics
1 answer:
shusha [124]3 years ago
4 0
Cmndkdkkdnd djnd dhdbhd s ahah who w baggage wbhebwnwh
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If our planet was twice as far away how would the Earth’s orbit change?
Tomtit [17]

Answer:

One of the indirect proofs that orbits change is actually in the growth of our own teeth when we were children. our teeth are some of the most basic, and primitive

parts of our bodies. They grow on a 9 day cycle, which was an ancient full moon to full moon cycle when the Earth and the Moon were a lot smaller, and closer together, and the co-orbital period was only 9 days, not the 29.5 days that it is currently.

So Given any two " Planets " that co-orbit a common gravitational center, the larger planet will grow larger far faster than the smaller planet, and the larger planet will accelerate the smaller planet to a higher orbit with a longer period, and decelerate itself to a lower orbit with a longer period, and the absolute value of the center to center distance will increase, and the orbital period will increase. The two orbs and their common gravitational center will remain co-linear through out the gradual growing and changing process.

This is an important process for the enlargement of the solar system as time passes, and an important process for larger galaxies as they attract and merge with smaller galaxies.

All of the planets grow larger at an accelerating rate, and thus systems spiral outward concentrating mass into larger and fewer galaxies, solar systems, and planet - moon systems.

5 0
2 years ago
Which statement relates most directly to the second law?
alukav5142 [94]
Statement three i do believe

7 0
3 years ago
Read 2 more answers
A 5000-lb wrecking ball hangs from a 50-ft cable of density 10 lb/ft attached to a crane. Calculate the work done if the crane l
aniked [119]

Answer:

total work is = 52450 J

Explanation:

given data

mass =  5000-lb

density = 10 lb/ft

height = 50 ft

solution

as we will treat here cable and ball are separate  

and

here work need to lift cable is

w = (10Δy )(9.8 y )  j

and

now summing all segment of cable

so passing limit Δy to 0

so total work need

= \int\limits^{10}_0 {98y} \, dy    

= [49 y^2]^{50}_0

= 2450J

so lifting 5000 lb wrcking 50 m  required additional 5000 + 2450

so total work is = 52450 J

3 0
3 years ago
A car and a lorry are about to collide. When they collide the two vehicles become tightly locked together. The lorry is going at
BartSMP [9]

Answer:

The speed of the vehicles immediately after the collision is 5.84 m/s.

Explanation:

The speed of the vehicles after the collision can be found by conservation of linear momentum:

p_{i} = p_{f}

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}

Where:

m₁: is the mass of the car = 0.5 ton = 500 kg

m₂: is the mass of the lorry = 9.5 ton = 9500 kg

v_{1_{i}}: is the initial speed of the car = 40 km/h = 11.11 m/s

v_{2_{i}}: is the initial speed of the lorry = 20 km/h = 5.56 m/s

v_{1_{f}}: is the final speed of the car =?

v_{2_{f}}: is the final speed of the lorry =?    

Since the two vehicles become tightly locked together after the collision v_{1_{f}} = v_{2_{f}}:

m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = v(m_{1} + m_{2})

v = \frac{m_{1}v_{1_{i}} + m_{2}v_{2_{i}}}{m_{1} + m_{2}} = \frac{500 kg*11.11 m/s + 9500 kg*5.56 m/s}{500 kg + 9500 kg} = 5.84 m/s

Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.

I hope it helps you!  

8 0
2 years ago
Marcia ran at a speed of 3.50 meters per second. How fast was she running in kilometers per hour?
RUDIKE [14]
3.5 meters per second

60sec=1min
60min=1 hr

3.5*60*60= meters per hour
=12600

1000meter= 1 km

12600/1000= km per hr
=12.6 km per hour
4 0
3 years ago
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