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sergeinik [125]
3 years ago
6

Is it true that atmospheric oxygen gas is a pure substance?

Physics
1 answer:
Mariana [72]3 years ago
3 0

The stronger the forces, the more rigid the matter. Pure Substances are made of the same material throughout and have the same properties throughout. Pure substances cannot be separated into other substances. Some examples are carbon, iron, water, sugar, salt, nitrogen gas, and oxygen gas.

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An ideal parallel - plate capacitor consists of two parallel plates of area A separated by a distance d. This capacitor is conne
Svetradugi [14.3K]

Answer:

The capacitance is cut in half.

Explanation:

The capacitance of a plate capacitor is directly proportional to the area A of the plates and inversely proportional to the distance between the plates d. So if the distance was doubled we should expect that the capacitance would be cut in half. That can be verified by the following equation that is used to compute the capacitance in such cases:

C = (\epsilon)*(A/d)

Where \epsilon is a constant that represents the characteristics for the insulator between the plates. A is the area of the plates and d is the distance between them. When we double d we have a new capacitance, given by:

C_new = (\epsilon)*(A/2d)

C_new = (1/2)*[(\epsilon)*(A/d)]

Since C = (\epsilon)*(A/d)] we have:

C_new = (1/2)*C

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3 years ago
The nucleus is found in the center of an atom options: True False
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It’s true all the way. It’s true
8 0
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scoray [572]
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3 years ago
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a) El Niño is defined as an abnormal weather pattern caused by the warming of the Pacific Ocean near the equator, off the coast of South America. The sun warms the water near the equator, which can make more clouds and, therefore, more rain. It has detrimental effects on biodiversity leading to its large-scale loss by
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A Carnot air conditioner operates between an indoor temperature of 20°C and an outdoor temperature of 39°C. How much energy does
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Answer:

D. 130 J

Explanation:

The coefficient of performance for a machine that is being used to cool, is given by:

COP=\frac{Q_C}{W}=\frac{T_C}{T_H-T_C}

Here Q_C  is the heat removed from the cold reservoir, W is the work required, that is, the energy required to remove the heat from the interior of the house, T_C is the cold temperature and T_H is the hot temperature. Recall use absolutes temperatures(273.15+^\circ C). Replacing and solving for W:

W=Q_c\frac{T_H-T_C}{T_C}\\W=2000J\frac{312.15K-293.15K}{293.15K}\\W=129.63J

8 0
4 years ago
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