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bija089 [108]
2 years ago
8

question 2(multiple choice worth 5 points) (01.07 mc) distances in space are measured in light-years. the distance from earth to

a star is 6.8 × 1013 kilometers. what is the distance, in light-years, from earth to the star (1 light-year
Physics
1 answer:
dlinn [17]2 years ago
7 0

The distance in light years from earth to Star is 7.1 Light Years.

We have the distance from earth to a star is 6.8 × 10^{13} kilometers.

We have to convert it into light years.

<h3>What is a Light Year?</h3>

Light year is a unit of astronomical distance equivalent to the distance that light travels in one year.

1 Light year = 9.4607 × 10^{12} km

According to the question, we have -

Distance from Earth to Star = 6.8 × 10^{13} km.

Now -

1 Light year = 9.4607 × 10^{12} km

or

9.4607 × 10^{12} km = 1 Light years

1 km = $\frac{1}{9.4607\times 10^{12} } Light years

Therefore -

6.8 × 10^{13} km = $\frac{6.8\times 10^{13} }{9.4607\times 10^{12} } = 0.71 x 10 = 7. 1 Light Years.

Therefore, the distance in light years from earth to Star is 7.1 Light Years.

To solve more questions on Light year, visit the link below-

brainly.com/question/13432741

#SPJ4

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LUCKY_DIMON [66]

Explanation :

It is given that,

Charge, q=1.3\times 10^{-16}\ C

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Distance, d=1.1\times 10^{-2}\ m

The work done is stored in the form of potential energy.

W=F.d

\because F=qE

So, W=qE\ d

W=1.3\times 10^{-16}\ C\times 3.2\times 10^2\ N/C\times 1.1\times 10^{-2}\ m

W=4.576\times 10^{-16}\ J

Hence, this is the required solution.

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3 years ago
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Write a hypothesis about the effect of the wavelength on the diffraction angle. Use the "if . . . then . . . because . . ." form
adell [148]
A) Wavelength is the distance between two successful crests or troughs in a transverse wave or the distance between two successful compressions or rarefactions in a longitudinal wave. if the wavelength of a wave is long then the wave will diffracts more compared to a wave with a shorter wavelength because the size of the wavelength is proportional to the angle of diffraction. Such that if the gap is larger than the wavelength then the wave passes through the gap and does not spread much on the other side, while when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread greatly out.

b) Diffraction is a phenomenon that occurs when a wave encounters an obstacles or a slit. It is referred to as the bending of light around corners of an obstacles or aperture into the region of geometrical shadow of the obstacle. It is caused by one wave of light is shifted by the diffracting object which will in turn cause the wave to have interference with itself. (either constructive or destructive)
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an average net force of 31.6 N is used to accelerate a 15.0 kg object uniformly from rest to 10.0 m/s leftward. What is the chan
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Answer:

-150 kg m/s

Explanation:

The change of momentum is calculated as ;

Δp= m*Δv where

where

Δp= change in momentum

Δv = vf-vi

m= mass of the object

Change in momentum is also calculated when using the formula;

Δp = F * Δt   when F is the net force applied and Δt is the time of action.

In this case;

m= 15 kg

vf=  -10 m/s

vi= 0 m/s

Taking rightward direction to be positive, then leftward will be negative.

Applying the formula as;

Δp = m*Δv

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Answer:

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Answer:

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Explanation:

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