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Murrr4er [49]
3 years ago
10

In a circuit, when the electrical resistance increases, the current _______ because it is _______ for the electrons to flow.

Physics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:

:)

Explanation:

no ones giving me answer to my question so here is this

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I’m tryna pass this class so pleaseee
Y_Kistochka [10]

Answer:

By looking at the graph it looks like its decreasing but you may want to re- read  the question to make sure that I am correct.I hope that this helps!

Explanation:

6 0
3 years ago
30 points to the first correct answer(btw they need to add a simple science subject).
NISA [10]

Electrical energy from the power socket

5 0
3 years ago
What is the wavelength in nm of a light whose first order bright band forms a
scoundrel [369]

The wavelength of the first order bright band light light is 714 nm .

Explanation:

We have to find the wavelength of the first order brightness of a light. Here we are using Huygen's principle of light.

The formula is

nλ =d sinθ

where, n is the order of maximum

            λ is the wavelength of light

            d is the distance between the lines on diffraction grating.

            θ is the angle.

For the given equation n is 1 because the problem states that the light forms 1st order bright band

  λ  is unknown.

d = \frac{1}{700,000} or 0.0000014 m

sin (30) = 0.5

so,

1(λ) = (0.0000014)(0.5)

     = 0.0000000714

     = 714 nm

Thus, The wavelength of the first order bright band light light is 714 nm .

3 0
4 years ago
15. Use the chemical equation below to determine how many moles of ammonia
Anastaziya [24]

Answer:

I'm not really sure but I think it is

four

6 0
3 years ago
Arrange the examples in order, starting with the object that has the least amount of energy. In each case, assume there’s no fri
Artemon [7]
First example: book, m= 0.75 kg, h=1.5 m, g= 9.8 m/s², it has only potential energy Ep,

Ep=m*g*h=0.75*9.8*1.5=11.025 J

Second example: brick, m=2.5 kg, v=10 m/s, h=4 m, it has potential energy Ep and kinetic energy Ek,

E=Ep+Ek=m*g*h + (1/2)*m*v²=98 J + 125 J= 223 J

Third example: ball, m=0.25 kg, v= 10 m/s, it has only kinetic energy Ek

Ek=(1/2)*m*v²=12.5 J.

Fourth example: stone, m=0.7 kg, h=7 m, it has only potential energy Ep,

Ep=m*g*h=0.7*9.8*7=48.02 J

The order of examples starting with the lowest energy:

1. book, 2. ball, 3. stone, 4. brick 


4 0
3 years ago
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