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Studentka2010 [4]
3 years ago
11

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
Lapatulllka [165]3 years ago
8 0

Answer:

Carry energy and momentum ... 10€. Frequency (Hz). Visible Light not to scale). Viclei | Blue Green | Yellow ... An absorbed photon can have an effect on electrons in an atom: ... To convert between eV's and Joules use the conversion (1eV = 1.6x10-19), ... h. 6.63 x 16 34 = 723 x 10Hz. 350. The energy of a photon varies.

Explanation:

i searched it on gogle

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What is the minimal mass of helium (density 0.18 kg/m3) needed to lift a balloon carrying two people in a basket, if the total m
Sergio039 [100]

Answer:   
 M[min] = M[basket+people+ balloon, not gas] * ΔR/R[b] 
 Î”R is the difference in density between the gas inside and surrounding the balloon. 
 R[b] is the density of gas inside the baloon.   
 ==================================== 
 Let V be the volume of helium required. 
 Upthrust on helium = Weight of the volume of air displaced = Density of air * g * Volume of helium = 1.225 * g * V   
 U = 1.225gV newtons 
 ---- 
 Weight of Helium = Volume of Helium * Density of Helium * g 
 W[h] = 0.18gV N   
 Net Upward force produced by helium, F = Upthrust - Weight = (1.225-0.18) gV = 1.045gV N  -----

 
 Weight of 260kg = 2549.7 N 
 Then to lift the whole thing, F > 2549.7 
 So minimal F would be 2549.7 
 ---- 
 1.045gV = 2549.7 
 V = 248.8 m^3   
 Mass of helium required = V * Density of Helium = 248.8 * 0.18 = 44.8kg (3sf)   
 =====   
 Let the density of the surroundings be R 
 Then U-W = (1-0.9)RgV = 0.1RgV   
 So 0.1RgV = 2549.7 N 
 V = 2549.7 / 0.1Rg   
 Assuming that R is again 1.255, V = 2071.7 m^3 
 Then mass of hot air required = 230.2 * 0.9R = 2340 kg   
 Notice from this that M = 2549.7/0.9Rg * 0.1R so   
 M[min] = Weight of basket * (difference in density between balloon's gas and surroundings / density of gas in balloon)   
 M[min] = M[basket] * ΔR/R[b]
3 0
3 years ago
Having aced your Physics 2111 class, you get a sweet summer-job working in the International Space Station. Your room-mate, Cosm
Sphinxa [80]

Answer:

a

The speed is   s =  5.857 m/s

b

The distance is  D = 22.4  \  m

Explanation:

From the question we are told that

     The speed of the banana is  v =  16 \ m/s

   The distance from my  location is  d =  8.2  \ m  

     The time taken is  t = 1.4 \ s

The speed of the ice cream is

          s =  \frac{d}{t}

substituting values

        s =  \frac{8.4}{1.4}

        s =  5.857 m/s

The distance of separation between i and Valdimir is the same as the distance covered by the banana

   So  

          D =  v * t

substituting values

        D = 16 *  1.4

        D = 22.4  \  m

     

3 0
3 years ago
A curve in a stretch of highway has radius R. The road is not banked in any way. The coefficient of static friction between the
adelina 88 [10]

Answer:

maximum possible velocity = \sqrt{ugR}

Explanation:

centripetal acceleration when the  car is going in the circle must be less than the maximum friction for the car to not slip.

centripetal acceleration \frac{mv^{2}}{r}

where v is the velocity of car and r is the radius of circle

maximum friction = umg

where u is the coefficient of static friction.

thereforeumg\geq \frac{mv^{2}}{R}

therefore maximum possible velocity = \sqrt{ugR}

6 0
3 years ago
(a) A standard sheet of paper measures 8 1/2 by 13 inches. Find the area of one such sheet of paper in m2.8.5(!meter/39.37in) —
Sergeu [11.5K]

Answer:

a)    A = 0.07129 m²

b)    A / A ’= 1.77

Explanation:

In this exercise we are asked to find the area in SI units, so let's start by reducing the dimensions to SI units.

width a = 8.5 inch (2.54 cm 1 inch) (1 m / 100 cm)

            a = 0.2159 m

length l = 13 inch (2.54 cm / 1 inch) (1 m / 100 cm)

              l = 0.3302 m

The area of ​​a rectangle is

            A = l a

             A = 0.3302 0.2159

             A = 0.07129 m²

b) we have a second sheet with reduced dimensions

         a ’= 3/4 a

         l ’= ¾ l

Let's find the area of ​​this glossy sheet

         A ’= l’ a ’

         A ’= ¾ l ¾ a

         A ’= 9/16 l a

To find the factor we divide the two quantities

           A / A ’= l a 16 / (9 l a

            A / A ’= 1.77

8 0
3 years ago
you see an insect egg lying on a leaf. What is the next step? Name or describe the stage you would expect to see come out from t
Marianna [84]

Answer:

Metamorphosis are the series of processes involved in the development of organisms, mostly insects after the egg is hatched.

Insects undergo complete or incomplete metamorphosis

Complete metamorphosis involves 4 stages which is the development from egg to larva to pups to adults in a step wise manner e.g butterfly, moth etc

Egg—> Larva—> Pupa—> Adults

In incomplete metamorphosis the stages are 3 and it involves development from egg to nymph to adults. E.g cockroach

Egg—> Nymph—> Adults

4 0
3 years ago
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