Question

Two protons in a molecule are 4.40 10-10 m apart. Find the electric force exerted by one proton on the other.

Answer 1

Answer:

F = 1.19 x 10⁹ N

Explanation:

The electrostatic force between the charged particles is given by Colomb's Law as follows:

$F = \frac{kq_{1}q_{2}}{r^{2}}$

where,

F = Electrostatic force = ?

k = Colomb's constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C

r = distance between protons = 4.4 x 10⁻¹⁰ m

Therefore,

$F = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(4.4\ x\ 10^{-10})^{2}}$

F = 1.19 x 10⁹ N