All categories

2 years ago

What is the probability of randomly selecting a z-score less than z = 2.25 from a normal distribution?

Physics

1 answer:

Vanyuwa [196]2 years ago

4 0

The probability of randomly selecting a z-score less than z = 2.25 from a normal distribution is 0.8944

Probability is the branch of arithmetic concerning numerical descriptions of ways in all likelihood an occasion is to occur, or how probably it's far that a proposition is genuine. The possibility of an event is a number between zero and 1, wherein, more or less talking, zero suggests the impossibility of the event and 1 shows the truth.

Probability = the range of methods of achieving achievement. the total range of viable results. As an example, the chance of flipping a coin and it being heads is ½, due to the fact there's 1 way of having a head and the full number of possible effects is two (a head or tail). We write P(heads) = ½ .

A probability is a range that reflects the danger or chance that a particular event will occur. Chances can be expressed as proportions that vary from 0 to at least one, and they also can be expressed as probabilities ranging from zero% to 100%.

Learn more about probability here brainly.com/question/24756209

#SPJ4

You might be interested in

a 2.0 kg ball is dropped from a height of 20 m onto a soft surface and rebounds to a height of 5.0 m . what is the magnitude of

Yuki888 [10]

Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.

<h3>What is the impulse of the floor on the ball?</h3>

Using the equation of motion to determine the velocity at the end of the fall

v^2 = u^2 + 2gh

Where v is velocity at the end of fall

u is initial velocity = 0

g is acceleration due to gravity = 9.81 m/s^2

h is height = 20

Taking downward velocity as negative and up as positive

v^2 = 0 + 2 (9.81)(20)

v^2 = 392.4

v = - 19.8 m/s

The velocity, v after bouncing is calculated also:

u = 0

g = 9.81 m/s^2

h = 5.0 m

v^2 = 0 + 2(9.81)(5)

v^2 = 98.1

v = 9.904 m/s

Impulse = change in momentum
Impulse = m(v- u)

Impulse = 2.0 × (9.9 -(-19.8)

Impulse = 59.4 Ns

Therefore, the impulse of the floor on the ball is 59.4 Ns.

Learn more about impulse at: brainly.com/question/904448

5 0

2 years ago

How much force does it take to stop a 1,000 kg car traveling at 20 m/s in 10 seconds?

Doss [256]

The initial momentum of the car is

(mass) x (speed) = 20,000 kg-m/s

"Impulse" is (force exerted) x (time the force lasts)
and it's equal to the change in momentum.

(Force) x (10 sec) = 20,000 kg-m/s

Divide each side by (10 sec) and you have

Force = (20,000 kg-m/s) / (10 sec)

= 2,000 kg-m/s² = 2,000 Newtons

5 0

3 years ago

A jogger is running outdoors on a cold day when the temperature is -20.0°C. She is breathing at the rate of 25 breaths per minut

Katyanochek1 [597]

Answer: 168606 J

Explanation:

Amount of heat lost is given by:

Q = m c ΔT

where, m is the mass of air inhaled, c is the specific heat of air and ΔT is the change in the temperature.

First, we will calculate the mass of air inhaled.

In each breath, jogger inhales 0.00450 m³ of air.

Breathing rate = 25 breathes per minute.

She jogs for 20 minutes.

So amount of air inhaled = 25 breathes per minute × 20 minutes × 0.00450 m³

Mass of air inhaled = density of air × volume of air inhaled

⇒ m = 1.29 kg/m³× 25 breathes per minute × 20 minutes × 0.00450 m³

⇒ m = 2.9 kg

Now, ΔT = T₂-T₁

T₁ = -20⁰C = -20 +273 K = 253 K

T₂ = 37⁰C = 37+273 K = 310 K

⇒ ΔT = T₂-T₁ = 310 K- 253 K = 57 K

Q = m c ΔT

⇒ Q = 2.9 kg × 1020 J/kg.K × 57 K = 168606 J

Thus, the jogger losses 168606 J amount of heat from breathing during 20 minutes of jogging.

3 0

3 years ago

Calculate the point of no return for an airport runway of 1.60 mi in length if a jet plane can accelerate at 10.1 ft/s2 and dece

Vilka [71]

Answer:

t = 26.39 s

Explanation:

given,

Length of runway = 1.60 mi = 8448 ft

acceleration of the jet = 10.1 ft/s²

deceleration of the jet = 7.21 ft/s²

Let x be the distance of no return

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 × 10.1 × x

v = √(20.2 x)

now, after reaching that Point the deceleration of the plane start

using equation of motion

final velocity of the first case will be the initial velocity of the second case

v² = u² + 2 a s

0 = 20.2 x - 2 x 7.21 x(8448-x)

34.62 x = 121820.16

x = 3518.78 ft

time taken to reach no return point

$x = ut+\dfrac{1}{2}at^2$

$3518.78 =\dfrac{1}{2}\times 10.1\times t^2$

t² = 696.788

t = 26.39 s

time taken to reach the no return point is equal to 26.39 s.

8 0

3 years ago

gravity on the surface of the Moon is only 1/6 as strong as gravity on the earth what is the weight of a 31 kg object on the ear

Effectus [21]

Answer:

IKLloolllwHi

░░░░░▐▀█▀▌░░░░▀█▄░░░

░░░░░▐█▄█▌░░░░░░▀█▄░░

░░░░░░▀▄▀░░░▄▄▄▄▄▀▀░░oxmsjiwikkw

░░░░▄▄▄██▀▀▀▀░░░░░░

░░░█▀▄▄▄█░▀▀░░

░░░▌░▄▄▄▐▌▀▀░░ This is Bob

░▐░░░▄▄░█░▀▀ ░░

▀█▌░░░▄░▀█▀░▀ ░░ Copy and paste him so he can take over brainly.

░░░░░░░▀███▀█░▄░░

░░░░░░▐▌▀▄▀▄▀▐▄░░

░░░░░░▐▀░░░░░░▐▌░░

░░░░░░█░░░░░░░░█░

Explanation:

7 0

2 years ago