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Gnom [1K]
3 years ago
14

Time period of a simple pendulum is measured at Karachi. What change will occur in the time period, if it is measured on mount e

verest, explain?
Physics
1 answer:
Reil [10]3 years ago
5 0
The period of a pendulum is given by T=2 \pi  \sqrt{ \frac{l}{g} }
since Karachi is near sea level, g is larger than it is on Mt. Everest.  That means the pendulum will have a larger period on Mt. Everest than it would in Karachi.
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Which of the following is a result of a change in pressure?
ioda
B. Exfoliation. Hope I helped you out bro.

7 0
4 years ago
A diver jumps off a diving platform that is 20 meters long. Describe the transfer of energy that occurs during the fall.
kobusy [5.1K]

Answer: gravitational potential energy is converted into kinetic energy

Explanation:

When the diver stands on the platform, at 20 m above the surface of the water, he has some gravitational potential energy, which is given by

E=mgh

where m is the man's mass, g is the gravitational acceleration and h is the height above the water. As he jumps, the gravitational potential energy starts decreasing, because its height h above the water decreases, and he acquires kinetic energy, which is given by

K=\frac{1}{2}mv^2

where v is the speed of the diver, which is increasing. When he touches the water, all the initial gravitational potential energy has been converted into kinetic energy.

8 0
3 years ago
Light of wavelength 600 nm passes though two slits separated by 0.22mm and is observed on a screen 1.1m behind the slits. The lo
Ne4ueva [31]

Answer:

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

Explanation:

We have to take into account the expression for the position of the fringes

dsen\theta=m\lambda\\y=\frac{m\lambda D}{d}

where m is the number of the maximum, d is the separation of the slits, D is the distance to the screen.

(a) By replacing we obtain

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

(b)  more information is required to solve this point. Please complete the information.

HOPE THIS HELPS!

4 0
3 years ago
Read 2 more answers
A student climbs to the top of the gym and drops a baseball to the ground below. A physics student standing nearby has a motion
sladkih [1.3K]

Answer:

The baseball was falling during 1.733 seconds.

Explanation:

The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground (t), measured in seconds, which is determined by the following kinematic formula:

t = \frac{v-v_{o}}{g} (1)

Where:

v_{o}, v - Initial and final speeds of the baseball, measured in meters per second.

g - Gravitational acceleration, measured in meters per square second.

If we know that v_{o} = 0\,\frac{m}{s}, v = 17\,\frac{m}{s} and g = 9.807\,\frac{m}{s^{2}}, then the time spent by the baseball is:

t = \frac{17\,\frac{m}{s}-0\,\frac{m}{s}  }{9.807\,\frac{m}{s^{2}} }

t = 1.733\,s

The baseball was falling during 1.733 seconds.

6 0
3 years ago
a 5.5kg box us pushed across the lunch table. the net force applied to the box is 9.7n. what is the acceleration of the box? ​
lys-0071 [83]

Answer:

1.76 m/s^2

Explanation:

The formula to find the force is F = ma (reference from 2nd law of Newton's Laws of Motion). Since you need to find the acceleration of the box, you need to use the formula a = f/m

a = 9.7 n divided by 5.5 kg = 1.76 m/s^2

4 0
3 years ago
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