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inna [77]
3 years ago
13

After a caterpillar eats a leaf, it can convert the chemical energy into _____ energy to help it build a cocoon.

Physics
2 answers:
umka21 [38]3 years ago
7 0
<span>After the caterpillar eats a leaf, it can convert the chemical energy into mechanical energy to help build a cocoon. The leaf as their source of food contains mostly of starch and cellulose. This must be break down into smaller compounds by enzymes. The smaller compounds will enter into the different parts of the caterpillars’ body for nutrition. The nutrients that are received by its body will be used for other body processes such as movement in building a cocoon.</span>
Oxana [17]3 years ago
4 0

Answer:

Mechanical

Explanation:

It uses mechanical energy to build a cocoon.

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The temperature of a sample of silver increased by 24.0 °C when 269 J of heat was applied. What is the mass of the sample?
statuscvo [17]

Answer:

Mass of the silver will be equal to 46.70 gram

Explanation:

We have given heat required to raise the temperature of silver by 24°C is 269 J , so \Delta T=24^{\circ}C

Specific heat of silver = 0.240 J/gram°C

We have to find the mass of silver

We know that heat required is given by

Q=mc\Delta T, here m is mass, c is specific heat of silver and \Delta T is rise in temperature

So 269=m\times 0.240\times 24

m = 46.70 gram

So mass of the silver will be equal to 46.70 gram

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Answer:B

Explanation:

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chubhunter [2.5K]

Answer:

The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.

hmax = 5740.48 m

Explanation:

This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.

V₀ = 420m/s and θ₀ = 53.0°

So, when the cannonball is fired it has horizontal and vertical components:

V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s

V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s

When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:

Vy = V₀y - g tₐ = 0

tₐ = V₀y/g

tₐ = (335.43m/s)/(9.8m/s²) = 34.23s

Then, the maximum height is reached in the instant tₐ = 34.23s:

h = V₀y tₐ - 1/2g tₐ²

hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²

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