<u>Answer:</u>
For 1: The correct answer is option D.
For 2: The correct answer is option A.
<u>Explanation:</u>
There are two types of molecules which can be categorized on the basis of electronegativity difference:
Polar molecules: In these type of molecules, the two atoms combining must be different so that a dipole can be created and for that the electronegativity of two atoms combining must not be same. The negative dipole of charge is created on the electronegative atom and positive dipole or charge is created on the electropositive atom.
Hence, the correct answer is option D.
Non-polar molecules are defined as the molecules which do not have any dipole and is formed when two atoms of same element combine together which have the same electronegativity. The electronegativity difference of these molecules is 0.
Hence, the correct answer is A.
False. gases have to greatest freedom of motion
Answer:
CN⁻
Explanation:
Oxyanion:
Oxyanion is the anion that have oxygen atom.
General formula:
The general formula for oxyanion is AₓOₓ⁻².
A = symbol of element combining with oxygen.
O = oxygen atom
z,x, = integers
a) = NO⁻
Its is an oxyanion because oxygen atom is present with nitrogen.
b) = SO₄⁻
It is an oxyanion because oxygen atom is present.
c) = CN⁻
This is not an oxyanion because there is no oxygen atom present.
d= CO₃²⁻
It is also an oxyanion because of presence of oxygen atom.
Answer:
The limiting reacting is O2
Explanation:
Step 1: data given
Number of moles O2 = 21 moles
Number of moles C6H6O = 4.0 moles
Step 2: The balanced equation
C6H6O + 7O2 → 6CO2 + 3H2O
Step 3: Calculate the limiting reactant
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
O2 is the limiting reactant. It will completely be consumed (21 moles).
C6H6O is in excess.
For 7 moles O2 we need 1 mol C6H6O
For 21 moles O2 we'll need 21/7 = 3 moles C6H6O
There will remain 4.0 - 3.0 = 1 mol C6H6O
Step 4: calculate products
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2
For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O
The limiting reacting is O2
