Question

If you use the approximate nonrelativistic equation for the magnitude of momentum of the proton, what answer do you get?

Answer 1

The answer is 4.96 * 10⁻¹⁹ kg m / s

Proton is an elementary particle that is identical to the nucleus of the hydrogen atom, along with the neutron is a constituent of all other atomic nuclei, that carries a positive charge numerically equal to the charge of an electron, and has a mass of 1.673 × 10−27 kilogram

nonrelativistic equation for the magnitude of the momentum of the proton is p = m * v

Then: p = m * v

Then Let's calculate its value

            After that p = 1.67 * 10⁻²⁷ * 0.99 * 3 * 10⁸

            Now, p = 4.96 * 10⁻¹⁹ kg m / s

hence the answer is 4.96 * 10⁻¹⁹ kg m / s

For more information on momentum click on the link below:

brainly.com/question/1042017

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