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Citrus2011 [14]
3 years ago
12

What's an acrostic poem for climate each line has to be written in a full sentence?

Physics
1 answer:
Mrac [35]3 years ago
3 0
Acrostic poem is a poem where the initials of the main word is given a respective sentence starting with that initial.
C- Can you see any changes happened in our surrounding?
L- Let me open your eyes and wake up to the reality.
I- Ignoring the unprecedented changes in our environment is worsening.
M- Making a move? Let's start it now.
A- Another day might not come.
T- Take this opportunity to show to world that we care.
E- Even to smallest thing that we can share.
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Drag the tiles to the correct boxes to complete the pairs.
marishachu [46]

Answer:

Air pollution---> smog

Water pollution---> eutrophication

Land pollution---> contaminated soil

Light pollution---> sky glow

7 0
3 years ago
I drove from Oklahoma to California (1452.9 miles) in 23 hours? What was my average speed?
storchak [24]

Answer:

63 miles per hour

Explanation:

you just divide miles and hours to get your average speed

5 0
2 years ago
How is heat transferred through radiation?
g100num [7]
A. Through the direct contact of particles
5 0
3 years ago
The attraction will vary directly with the separation between the charges.
Burka [1]
No it won't. It'll vary inversely as the square of the separation.
4 0
2 years ago
A stone is thrown towards a wall with an initial velocity of v0=19m/s and an angle = 71 with the horizontal, as illustrated in t
HACTEHA [7]

Answer:

(a) 2.85 m

(b) 16.5 m

(c) 21.7 m

(d) 22.7 m

Explanation:

Given:

v₀ₓ = 19 cos 71° m/s

v₀ᵧ = 19 sin 71° m/s

aₓ = 0 m/s²

aᵧ = -9.8 m/s²

(a) Find Δy when t = 3.5 s.

Δy = v₀ᵧ t + ½ aᵧ t²

Δy = (19 sin 71° m/s) (3.5 s) + ½ (-9.8 m/s²) (3.5 s)²

Δy = 2.85 m

(b) Find Δy when vᵧ = 0 m/s.

vᵧ² = v₀ᵧ² + 2 aᵧ Δy

(0 m/s)² = (19 sin 71° m/s)² + 2 (-9.8 m/s²) Δy

Δy = 16.5 m

(c) Find Δx when t = 3.5 s.

Δx = v₀ₓ t + ½ aₓ t²

Δx = (19 cos 71° m/s) (3.5 s) + ½ (0 m/s²) (3.5 s)²

Δx = 21.7 m

(d) Find Δx when Δy = 0 m.

First, find t when Δy = 0 m.

Δy = v₀ᵧ t + ½ aᵧ t²

(0 m) = (19 sin 71° m/s) t + ½ (-9.8 m/s²) t²

0 = t (18.0 − 4.9 t)

t = 3.67

Next, find Δx when t = 3.67 s.

Δx = v₀ₓ t + ½ aₓ t²

Δx = (19 cos 71° m/s) (3.67 s) + ½ (0 m/s²) (3.67 s)²

Δx = 22.7 m

7 0
3 years ago
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