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iren [92.7K]
2 years ago
10

Giving brainly if correct show work​

Physics
1 answer:
Orlov [11]2 years ago
5 0

Answer:

Umm Lucy will weigh to many pounds

Explanation:

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Calculate the density of the football. Use the formula D = m/V where D is the density, m is the mass, and V is the volume. Recor
s344n2d4d5 [400]

Answer:

Detailed explanation:

Density of water=1000kg/m³

Hence mass of water displaced is:

m=d×v

=1000kg/m³×(4.3×10^-3)m³ (volume of water displaced converted to L)

=4.3 kg of water

Hence, mass of football is also 4.3 kg(Archimedes principle)

Thus density of football

=mass÷volume

substitute the mass and volume and solve.

hope this helps

4 0
3 years ago
Read 2 more answers
A 5kg object is moving downward at a speed of 12m/s. If it is currently 2.6m above the ground, what is its kinetic energy?
Nookie1986 [14]

Answer:

360J

Explanation:

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body when decelerating from its current speed to a state of rest.

5 0
3 years ago
Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
Aleonysh [2.5K]

De broglie wavelength, \lambda = \frac{h}{mv}, where h is the Planck's constant,  m is the mass and v is the velocity.

h = 6.63*10^{-34}

Mass of hydrogen atom,  m = 1.67*10^{-27}kg

v = 440 m/s

Substituting

   Wavelength \lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m

1 pm = 10^{-12}m\\ \\ So , \lambda =902 pm

So  the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

7 0
3 years ago
A friend on skis stands still on level ground, with dry 0.00°C with a coefficient of static friction of 0.0300. How hard would y
Salsk061 [2.6K]

Answer:

20.6 N

Explanation:

Friction equals normal force times coefficient of friction.

F = Fn μ

On level ground, normal force equal weight.

Fn = W

Therefore:

F = W μ

F = (685 N) (0.0300)

F = 20.6 N

6 0
3 years ago
Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87
marshall27 [118]

Answer:

a)  \lambda=0.935\ \textup{m}

b) f=36.19\approx 36\ \textup{Hz}

Explanation:

Given:

String vibrates transversely fourth dynamic, thus n = 4

mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg

Tension in the string, T = 8.39 N

Length of the string, L = 1.87 m

a) we know

L= n\frac{\lambda}{2}

where,

\lambda = wavelength

on substituting the values, we get

1.87= 4\times \frac{\lambda}{2}

or

\lambda=0.935\ \textup{m}

b) Speed of the wave (v) in the string is given as:

v =f\lambda

also,

v=\sqrt\frac{T}{(\frac{m}{L})}

equating both the formula for 'v' we get,

f\lambda=\sqrt\frac{T}{(\frac{m}{L})}

on substituting the values, we get

f\times 0.935=\sqrt\frac{8.39}{(\frac{13.7\times 10^{3}}{1.87})}

or

f=\frac{33.84}{0.935}

or

f=36.19\approx 36\ \textup{Hz}

5 0
3 years ago
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