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marysya [2.9K]
2 years ago
5

Two athletes are competing in upcoming competitions, a weightlifting meet and a marathon. which energy systems will each be prim

arily using, respectively?
Physics
2 answers:
Tema [17]2 years ago
8 0

Answer:

Explanation:

How did media attention affect Barack Obama's presidential performance?(A)(B)(C)(D)He made a concerted effort to listen to Congress' concerns about his policies.He decided to go on Fox News in an attempt to win over Republican voters.He started traveling the country to give speeches about his policy goals.He began meeting in private with Speaker of the House Nancy Pelosi.

Paha777 [63]2 years ago
7 0

Two athletes are competing in upcoming competitions, a weightlifting meet and a marathon. phosphagen and oxidative energy systems will each be primarily used, respectively.

As it is in charge of high-intensity, brief-duration activity, the phosphagen energy systems generate energy for jumping and sprinting. The quickest and most effective energy producer in muscle activity. Phosphagen metabolism is demonstrated by this system. It uses creatine phosphate to produce ATP (adenosine triphosphate, the chemical which provides energy for all body processes).

Energy is produced by the oxidative energy systems using 30% and 70% of carbs and lipids, respectively. When done for at least 150 minutes a week, aerobic exercise enables the body to experience physiological and health benefits.

Learn more about phosphagen here: brainly.com/question/15328745

#SPJ4

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A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)
salantis [7]

Answer:

<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>

Explanation:

The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.

Given are

   <em>  mass of the student 73 kg</em>

<em>      height of water glide 11.8 m</em>

<em>      work done as -5.5*10³ J</em>

Have to find speed at which the student goes down the glide.

According to<em> Law of Conservation of energy</em>,

          K.E =P.E+Work Done

 mv²/2=mgh +W

Rearranging the above eqn for v

v = √2(gh+W/m)

Substituting values,

V =  12.48 m/s.

<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>

 

3 0
3 years ago
Two separate masses on two separate springs undergo simple harmonic motion indefinitely (the surface is frictionless). In CASE 1
Artemon [7]

Answer:

\frac{F_1}{F_2} =\frac{1}{2}

Explanation:

Assuming the we have to find ratio maximum forces on the mass in each case

we know that in a spring mass system

F= Kx

K= spring constant

x= spring displacement

Case 1:

F_1=2k\times d

case 2:

F_2=2k\times 2d

therefore, \frac{F_1}{F_2} = \frac{2K\times d}{2K\times 2d}

\frac{F_1}{F_2} =\frac{1}{2}

4 0
4 years ago
1.) Balance the following chemical equation: ___KOH + ___H₃PO₄ → ____K₃PO₄ + ___H₂O 2.) Balance the following chemical equation:
Akimi4 [234]

Answer:

The first one put 1's

Explanation:

7 0
4 years ago
A stone is thrown horizontally from 2.4m above the ground at 35m/s. The wall is 14m away and 1m high.At what height the stone wi
KIM [24]

The stone reaches the wall at a height of <u>1.62 m</u>.

The stone lands at a point <u>24.5 m</u> from the point of projection.

The stone is projected horizontally with a velocity u at a height <em>h</em> from the ground. The wall is located at a distance <em>x</em> from the point of projection. The stone takes a time <em>t</em> to reach the wall and in the same time the stone falls a vertical distance <em>y</em>.

The horizontal distance <em>x</em> is traveled with a constant velocity <em>u</em>.

x=ut

Calculate the time taken <em>t</em>.

t=\frac{x}{u} \\ =\frac{14m}{35 m/s} \\ =0.40s

The stone's initial vertical velocity is zero. It falls through a distance <em>y</em> in the time <em>t</em> under the action of acceleration due to gravity <em>g</em>.

y=\frac{1}{2} gt^2\\ \frac{1}{2} (9.81m/s^2)(0.40s)^2\\ =0.784m

The height  <em>h₁ </em>of the stone above the ground when it reaches the wall  is given by,

h_1=h-y\\ =(2.4m)-(0.784m)\\ =1.616m=1.62m

When the stone reaches the wall, its height from the ground is <u>1.62m.</u>

The stone thus crosses over the wall, since the height of the wall is 1 m. It reaches the ground at a distance <em>R</em> from the point of projection. If the time taken by the stone to reach the ground is <em>t₁, </em>then,

h=\frac{1}{2} gt_1^2

Calculate the time taken by the stone to reach the ground.

t_1=\sqrt{\frac{2h}{g} } \\=\sqrt{\frac{2(2.4m)}{9.81m/s^2} } \\ =0.699 s

The horizontal distance traveled by the stone is given by,

R=ut_1 \\ =(35m/s)(0.699s)\\ =24.5m

The stone lands at point 24.5 m from the point of projection and 10.5 m from the wall.

3 0
3 years ago
Which number is not rounded correctly?
DedPeter [7]
The answer would be <span>B. 210.8 rounded to 210

When rounding, if the digit you are rounding is equal to or larger than 5, you round the number up. For example: 15 rounded up to 20. 99 rounded up to 100.

210.8 would be rounded up to 211 
because the 8 is greater than five, so you have to round it up.</span>
5 0
3 years ago
Read 2 more answers
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