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ioda
3 years ago
6

A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)

acts on her. The student has a mass of 73 kg, and the height of the water slide is 11.8 m. If the kinetic frictional force does -5.5 × 103 J of work, how fast is the student going at the bottom of the slide?
Physics
1 answer:
salantis [7]3 years ago
3 0

Answer:

<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>

Explanation:

The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.

Given are

   <em>  mass of the student 73 kg</em>

<em>      height of water glide 11.8 m</em>

<em>      work done as -5.5*10³ J</em>

Have to find speed at which the student goes down the glide.

According to<em> Law of Conservation of energy</em>,

          K.E =P.E+Work Done

 mv²/2=mgh +W

Rearranging the above eqn for v

v = √2(gh+W/m)

Substituting values,

V =  12.48 m/s.

<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>

 

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