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Nadya [2.5K]
3 years ago
11

in triangle abc, angle b is 10 degrees greater than angle a. Angle c is twice as much as angle A. what's the measure of each ang

le?
Mathematics
1 answer:
yuradex [85]3 years ago
6 0
The sum of the angles of a triangle is 180 degrees.
a + b + c = 180.
a + (a+10) + 2a = 180
3a + 10 = 180
3a + 10 - 10 = 180 - 10
3a = 170
a = 42.5 degrees
b= 52.5 degrees and c = 85 degrees.
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A side of the triangle below has been extended to form an exterior angle of 128°. Find the value of x.
denis23 [38]

Answer:

x = 104

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

24+x = 128

Subtract 24 from each side

24+x-24 =128 -24

x =104

3 0
3 years ago
I need help with 12,19, and 21
lorasvet [3.4K]
17. 4 , 19. -154 , 21. 2
6 0
3 years ago
4y+12=0<br> How do I get the two points to be graphed
coldgirl [10]

Did somebody say you're supposed to draw the graph of the equation ?
Is that the assignment ?

OK.  Just like every other equation you need to graph, get it in the
standard form, where 'y' is all alone on one side, and everything else
is on the other side.  When you do that, you'll be able to spot the slope
and y-intercept of the  line, or get some points, or whatever you want.

                                               4y + 12  =  0

Subtract 12 from each side:          4y  =  -12

Divide each side by 4:                      y  =  -3

There's the equation you can handle. 
The y-intercept is -3, and the slope is zero.

Would you like some points ?  OK.  Pick a couple of values for 'x',
and calculate the value of 'y' for each one:

The first value I picked for 'x':  x = 72 
The equation is  y=-3, so when x=72, y=-3.  The point is (72, -3)

The second value I picked for 'x' is:  x = 1
The equation is  y=-3, so when x=1,  y=-3.    The second point is (1, -3).

The third value I picked for 'x' is 4 billion.
The equation is  y=-3, so when x=4 billion, y=-3.  The third point is  (1, -3).

Do you see what's going on here ?  Your original equation didn't even
have 'x' in it, so we could tell right away that when the graph is drawn,
the value of 'y' at every point can't depend on 'x'.

When we simplified the equation and got it in standard form, we found that
the slope of the graph is zero.  That means the graph doesn't rise or fall ...
it's just a horizontal line.  Sure enough, the height of points on the line
doesn't depend on 'x'.  The value of 'y' at every point on the line is  -3 .
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=938%20%5Ctimes%206" id="TexFormula1" title="938 \times 6" alt="938 \times 6" align="absmiddle"
Assoli18 [71]

938* 6=

5628

The answer s 5628

6 0
3 years ago
Read 2 more answers
If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes
anyanavicka [17]

ANSWER

x  =  2 \: \: or \:  \:  x  =  15

Or

x  =   - 2 \: \: or \:  \:  x  =   -  15

EXPLANATION

The given polynomial is

f(x) = {x}^{2}  + kx + 30

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

m + n =  -  \frac{b}{a}  =  -k

and the product of roots is

mn =  \frac{c}{a}  = 30

The square difference of the zeroes is given by the expression.

( {m - n})^{2} =  {(m + n)}^{2} - 4mn

From the question, this difference is 169.

This implies that:

( { - k)}^{2}  - 4(30) = 169

{  k}^{2}  -120= 169

k^{2} = 289

k=  \pm \sqrt{289}

k=  \pm17

We substitute the values of k into the equation and solve for x.

f(x) = {x}^{2}   \pm17x + 30

f(x) = (x  \pm2)(x  \pm 15)

The zeroes are given by;

(x  \pm2)(x  \pm 15) = 0

x  =  \pm2 \: \: or \:  \:  x  =  \pm 15

5 0
3 years ago
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