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1 year ago

9

Connie and Sadie are having a conversation and are talking about how good looking Mark is. Sadie says to Connie, "Mark is SO hot

!" The word "hot" in this phrase is an example of what type of meaning of the word?

1 answer:

Katen [24]1 year ago

3 0

Answer:

he is just so scrumptious

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Simplify the following expression.

solong [7]

Answer:

B. $\frac{1}{64}$

in decimal form, it would be 0.015625

5 0

2 years ago

Amy is 4 years older than April. Together, their age is 24. How old is April and how old is Amy?

fomenos

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7 0

3 years ago

79 x 31 rounding or compatible numbers . show how you estimate

Lubov Fominskaja [6]

Answer:

80 × 30 = 2,400

Step-by-step explanation:

We can easily round 79 up to 80 and round 31 down to 30. This would make our expression 80 × 30, which is much easier to compute. We just take 8 × 3 (which is 24) and add two zeros onto the end of the number. This yields us an answer of 2,400 which is very close to the actual multiplication of 79 × 31 which is 2,449 (only 49 more than our estimation).

8 0

2 years ago

Find the value of $ 15,000 at the end of one year if it is invested in an account that has an interest rate of 4.95 % and is com

lora16 [44]

A)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{twelve months, thus}
\end{array}\to &12\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{12}\right)^{12\cdot 1}$

b)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{365 days, thus}
\end{array}\to &365\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{365}\right)^{365\cdot 1}$

c)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{four quarters, thus}
\end{array}\to &4\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{4}\right)^{4\cdot 1}$

7 0

3 years ago

Aidan read 5 pages for every 3 pages

OlgaM077 [116]

Answer:

35 pages

Step-by-step explanation:

5-3=2

14÷2=7 sets

Hence, no. of pages Aiden read=5×7

=35 pages

3 0

3 years ago

Read 2 more answers