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Leto [7]
1 year ago
9

What is the bulk modulus of oxygen if 34.3 g of oxygen occupies 27.9 l and the speed of sound in the oxygen is 342 m/s?

Chemistry
1 answer:
Neko [114]1 year ago
8 0

The density of oxygen gas is

ρ= 0.0224 m 3

0.0320 kg

​=1.43 kg/m 3

From v= B/ρ

​we find

B=v 2  ρ

=(317 m/s) 2  (1.43 kg/m 3 )

=1.44×10 5  Pa.

Speed of sound

The speed of sound is the distance travelled per unit of time by a sound wave as it propagates through an elastic medium. At 20 °C (68 °F), the speed of sound in air is about 343 metres per second (1,125 ft/s; 1,235 km/h; 767 mph; 667 km), or one kilometre in 2.9 s or one mile in 4.7 s. It depends strongly on temperature as well as the medium through which a sound wave is propagating. At 0 °C (32 °F), the speed of sound in air is about 331 m/s (1,086 ft/s; 1,192 km/h; 740 mph; 643 km).

To learn more about the speed of sound refer here:

brainly.com/question/15381147

#SPJ4

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liquid octane(CH3)(CH2)6CH3) reacts with gaseous oxygen gas(O2) to produce gaseous carbon dioxide(CO2) and gaseous water(H2O). I
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The percent yield of carbon dioxide will be 49.0 %.

<h3>Percent yield</h3>

First, let's look at the equation of the reaction:

2C_8H_1_8 + 25O_2 -- > 16CO_2 + 18H_2O

The mole ratio of octane to oxygen is 2:25.

Mole of 3.43 g octane = 3.43/114.23 = 0.03 mol

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Thus, octane is limiting.

Mole ratio of octane to carbon dioxide = 2:16.

Equivalent mole of carbon dioxide = 0.03 x 8 = 0.24 mol

Mass of 0.24 mol carbon dioxide = 0.24 x 44.01 = 10.5624 grams

Percent yield of carbon dioxide = 5.18/10.5624 = 49.0 %

More on percent yield can be found here: brainly.com/question/17042787

#SPJ1

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