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3 years ago

do ionic, covalent and metallic bonds form molecular or ionic compounds? HELP PLEASE I WILL MARK BRAINLIEST

Chemistry

1 answer:

Svetradugi [14.3K]3 years ago

8 0

Answer:

Ionic compounds contains ionic bond

Like NaCl

Molecular compounds contains covalent bond like H2O

And metals contains metalic bond like in copper

Explanation:

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Whitepunk [10]

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2 years ago

Non example of eukaryote cell

Rom4ik [11]

Bacteria are the only type of cells that are not eukaryotic.

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3 years ago

Refer to the reaction between magnesium and oxygen In the introduction. What elements is oxidizing?write the oxidation number fo

erica [24]

Answer:

Oxidizing element: Mg

Explanation:

Reaction of magnesium and oxygen can be written as:

$2Mg +O_2 \rightarrow 2MgO$

while writting chemical reaction between two atom or element then write their natural form i.e. how that atom or element exist in the nature.

eg. reaction of any element with Oxygen atom then we can not write directly O because oxygen exist in the nature in form of $O_2$

finding oxidation number each side:

Reactant side:

Mg=0;

O=0;

product side:

Mg=+2;

O=-2;

from above:

oxidation number of Mg is increasing hence this is oxidizing element

7 0

3 years ago

5. A gas occupies 2000. Lat 100.0 K and exerts a pressure of 100.0 kPa. What volume will

Anna [14]

Answer:

4000 L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Initial volume (V1) = 2000 L.

Initial temperature (T1) = 100 K.

Initial pressure (P1) = 100 kPa.

Final temperature (T2) = 400 K.

Final pressure (P2) = 200 kPa.

Final volume (V2) =..?

Step 2:

Determination of the new volume of the gas.

The new volume of the gas can be obtained by using the general gas equation as follow:

P1V1/T1 = P2V2/T2

100 x 2000/100 = 200 x V2/400

Cross multiply to express in linear form.

100 x 200 x V2 = 100 x 2000 x 400

Divide both side by 100 x 200

V2 = (100 x 2000 x 400)/(100 x 200)

V2 = 4000 L

Therefore, the new volume of the gas is 4000 L

5 0

3 years ago

How many moles in 2.21 x10E24 atoms of aluminum

lisov135 [29]

<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})$
Divide: $\displaystyle 3.66988 \ mol \ Al$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.66988 mol Al ≈ 3.67 mol Al

7 0

3 years ago