Given that,
The diameter of a tennis ball, d = 2.7 inches
Radius, r = 1.35 inches
The dimensions of the storage shed is 14 feet wide, 15 feet long, and 10 feet high.
Volume of the shed is, V = lbh
![V=14\times 15\times 10\\\\V=2100\ \text{feet}^3](https://tex.z-dn.net/?f=V%3D14%5Ctimes%2015%5Ctimes%2010%5C%5C%5C%5CV%3D2100%5C%20%5Ctext%7Bfeet%7D%5E3)
We can convert radius from inches to feet :
1 foot = 12 inches
Radius, r = 0.1125 feet
Let there are x number of tennis balls that can fit in the shed. So,
![x\times V_b=V_s\\\\\text{Where}\ V_b\ \text{and}\ V_s\ \text{volume of ball and shed}\\\\x=\dfrac{V_s}{\dfrac{4}{3}\pi r^3}\\\\x=\dfrac{2100}{\dfrac{4}{3}\pi \times (0.1125)^3}](https://tex.z-dn.net/?f=x%5Ctimes%20V_b%3DV_s%5C%5C%5C%5C%5Ctext%7BWhere%7D%5C%20V_b%5C%20%5Ctext%7Band%7D%5C%20V_s%5C%20%5Ctext%7Bvolume%20of%20ball%20and%20shed%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7BV_s%7D%7B%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B2100%7D%7B%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20%5Ctimes%20%280.1125%29%5E3%7D)
x = 352105.75 balls
or
x = 352106 balls
Hence, 352106 balls can fit in the storage shed.