Answer:
Explanation:
We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 16.04 32.00 44.01 18.02
CH₄ + 2O₂ → CO₂ + 2H₂O
m/g: 10.0 40.0
1. Moles of CH₄
2. Mass of CO₂
(i) Calculate the moles of CO₂
The molar ratio is (1 mol CO₂ /1 mol CH₄)
(ii) Calculate the mass of CO₂
3. Mass of H₂O
(i) Calculate the moles of H₂O
The molar ratio is (2 mol H₂O /1 mol CH₄)
(ii) Calculate the mass of H₂O
To calculate the concentration of the base based on the titration, the concept used is the equal of number of equivalence of the acid used to that of the base. From this,
Na x Va = Nb x Vb
For HBr and KOH, molarity is equal to normality. Substituting the known values,
(0.75 M) x (22.6 mL - 0 mL) = Nb x (37.5 mL - 0.5 mL)
Nb = 0.46 N
Mb = 0.46 M
Thus, the concentration of the base is approximately 0.46 M.
Answer:
The number before any molecular formula applies to the entire formula. So here you have five molecules of water with two hydrogen atoms and one oxygen atom per molecule. Thus you have ten hydrogen atoms and five oxygen atoms in total.
A salt and water I believe
Answer: = D
Explanation:
The atomic mass increases from Ne to O2 to Cl2 hence the boiling point also increases, therefore
Ne < O2 < Cl2