An arrow is moving at 35m/sand travels for 5 seconds.how far did the arrow travel?

Calculate the percent dissociation of benzoic acid C6H5CO2H in a 2.4mM aqueous solution of the stuff. You may find some useful d

Musya8 [376]

Answer:

34%

Explanation:

5 0

2 years ago

What volume of a 1.5 M KOH solution is needed to provide 3.0 moles of KOH?

Brums [2.3K]

Answer:

Volume = 2.0 liter of 1.5 M solution of KOH

Explanation:

1) Data:

a) Solution: KOH

b) M = 1.5 M

c) n = 3.0 mol

d) V = ?

2) Formula:

Molarity is a unit of concentration, defined as number of moles of solute per liter of solution:

M = n / V in liter

3) Calculations:

Solve for n: M = n / V ⇒ V = n / M

Substitute values: V = 3.0 mol / 1.5 M = 2.0 liter

You must use 2 significant figures in your answer: 2.0 liter.

8 0

2 years ago

In the laboratory you are asked to make a 0.565 m sodium bromide solution using 315 grams of water. How many grams of sodium bro

Scorpion4ik [409]

Answer : The mass of sodium bromide added should be, 18.3 grams.

Explanation :

Molality : It is defined as the number of moles of solute present in kilograms of solvent.

Formula used :

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}$

Solute is, NaBr and solvent is, water.

Given:

Molality of NaBr = 0.565 mol/kg

Molar mass of NaBr = 103 g/mole

Mass of water = 315 g

Now put all the given values in the above formula, we get:

$0.565mol/kg=\frac{\text{Mass of NaBr}\times 1000}{103g/mole\times 315g}$

$\text{Mass of NaBr}=18.3g$

Thus, the mass of sodium bromide added should be, 18.3 grams.

6 0

2 years ago

Calculate the percent errorin a length measurementof 4.45cm if the correct value is 4.06

FinnZ [79.3K]

Answer:

9.6 %

Explanation:

Step 1: How to define percent error ?

⇒ % error is the difference between a measured value and the known or accepted value

⇒Percent error is calculated using the following formula:

⇒%error = | Experimental value-theoretical value/theoretical value | x100%

⇔ this can be written as well as : error = (| Experimental value/ theoretical value | - | Theoretical value / Theoretical value | ) x100%

Step 2: Calculate % error

In this case, this means :

%error = ( |(4.45 cm - 4.06cm ) / 4.06cm | ) x100%

%error = 0.096 x100%

%error =9.6 %

3 0

2 years ago

An orbital of an atom is defined as the most probable location of(1) an electron (2) a neutron (3) a positron (4) a proton

Montano1993 [528]

Answer: option (1) an electron.

Justification:

1) The plum pudding model of the atom conceived by the scientist J.J. Thompson, described the atom as a solid sphere positively charged with the electrons (particles negatively charged) embedded.

2) The next model of the atom, developed by the scientist Ernest Rutherford, depicted the atom a mostly empty space with a small dense positively charged nucleous and the electrons surrounding it.

3) Then, Niels Bhor came out with the model of electrons in fixed orbits around the nucleous, just like the planets orbit the Sun. So, the path followed by the electrons were orbits.

4) The quantum model of the atom did not place the electrons in fixed orbits around the nucleous but in regions around the nucleous. Those regions were named orbitals. And they are regions were it is most probable to find the electron, since it is not possible to tell the exact position of an electron.

As per this model, the electron has a wave function associated. The scientist Schrodinger developed the wave equation which predicts the location of the electron as a probability.

The orbitals are those regions were it is most likely to find the electron. Those regions are thought as clouds of electrons.

5 0

3 years ago

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