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3 years ago

If 550 mL of a 3.50 M KCl solution are set aside and alowed to evaporate unti the

Chemistry

1 answer:

andrezito [222]3 years ago

5 0

1) list givens and convert if necessary

C₁ = 3.50 mol/L

V₁ = 0.550 L

C₂ = ?

V₂ = 0.275 L

2) rearrange formula

$C_{1}V_{1}=C_{2}V_{2}\\\\C_{2}=\frac{C_{1}V_{1}}{V_{2}}$

3) solve

$C_{2}=\frac{(3.50\ mol/L)(0.550\ L)}{(0.275\ L)}$

C₂ = 7.00 mol/L

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Correct answers: 2 and 3

Explanation:

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3 years ago

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3 years ago

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jek_recluse [69]

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For oxygen gas:

$\text{Moles of oxygen gas}=\frac{2.5g}{32g/mol}=0.078mol$

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$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

By Stoichiometry of the reaction:

4 moles of aluminium reacts with 3 moles of oxygen.

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As, given amount of oxygen is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of aluminium produce = 2 moles of $Al_2O_3$

So, 0.092 moles of aluminium will produce = $\frac{2}{4}\times 0.092=0.046moles$ of $Al_2O_3$

Now, calculating the mass of aluminium oxide:

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Hence, the percent yield of the reaction is 74 %

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3 years ago

If gas in a sealed container has a pressure of 50 kPa at 300 K, what will the pressure be if the temperature rises to 360 K?

VLD [36.1K]

The answer is 60 kpa, also did you try look it up because that is what i did but i did not copy and paste it.

hope this helped have a good day

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3 years ago