Question

If 550 mL of a 3.50 M KCl solution are set aside and alowed to evaporate unti the

Answer 1

1) list givens and convert if necessary

C₁ = 3.50 mol/L

V₁ = 0.550 L

C₂ = ?

V₂ = 0.275 L

2) rearrange formula

$C_{1}V_{1}=C_{2}V_{2}\\\\C_{2}=\frac{C_{1}V_{1}}{V_{2}}$

3) solve

$C_{2}=\frac{(3.50\ mol/L)(0.550\ L)}{(0.275\ L)}$

C₂ = 7.00 mol/L