3 years ago

Which of the ordered pairs in the form ( x,y) is a solution of this equation 3x+2y=6

Mathematics

2 answers:

Alona [7]3 years ago

4 0

Answer:

(2,0), (0,3), (1 3/5)

Step-by-step explanation:

timama [110]3 years ago

4 0

3x + 2y = 6
3x = 6-2y
x = 2 - 2/3y

You would need to give more than one equation...

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klasskru [66]

$\bf |x^2+3x-1|\ \textless \ 3\implies 
\begin{cases}
+(x^2+3x-1)\ \textless \ 3\\\\
-(x^2+3x-1)\ \textless \ 3
\end{cases}\\\\
-------------------------------\\\\
x^2+3x-1\ \textless \ 3\implies x^2+3x-4\ \textless \ 0\implies (x+4)(x-1)\ \textless \ 0
\\\\\\
x\ \textless \ 
\begin{cases}
-4\\
1
\end{cases}\\\\
-------------------------------\\\\
-(x^2+3x-1)\ \textless \ 3\implies x^2+3x-1\boxed{\ \textgreater \ }-3
\\\\\\
x^2+3+2\ \textgreater \ 0\implies (x+2)(x+1)\ \textgreater \ 0\implies x\ \textgreater \ 
\begin{cases}
-2\\
-1
\end{cases}$