Answer:

Step-by-step explanation:

Answer: w + 5
Step-by-step explanation: The sum of w and 5 translates into an algebraic expression form to w + 5.
Answer:
40cm
Step-by-step explanation:
A=s*s
A=10*10
A=100 cm^2
P=4*s
P=4*10
P=40 cm
"s" represents side
Y = money left over
X = fair ticket
Y = 36.75 - 3x
Given expression is

Now we need to simplify this expression. We can begin by factoring numerator and denominator if possible.

divide numerator and denominator both by 2v


Hence final answer is 
Or you can also keep factored form
