Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
it might go like A= 12 B= 0 C = -6
Answer: 13,333 snowflakes
Step-by-step explanation:
For this exercise let be "x" represents the number of snowflakes that will be in the fort.
According to the information given in the exercise, the weight of one block is 1 kilogram. Knowing that the fort must have 40 blocks, the total weight is:
Since each snowflake weighs 
grams, need to divide the total weight calculated above by the weight of a snowfake.
Therefore, through this procedure you get the following result:
Therefore, the there will be 13,333 snowflakes in the fort.
Answer:
6 Hours
Explanation:
Linear Equation: mx+b=y
x variable: Hour
Hourly Fee: $15(x)
(Initial) Rent Fee: $25
Balance: $100
Equation:
15x+25=100
15x+25-25=100-25 -- <em>Separate the constant terms from the x by subtracting 25 from both sides.</em>
15x=100
15x/15=100/15 --<em> Isolate the x variable by dividing 15 from both sides.</em>
x=6.6.. <em>-- Round down to 6 (not 7) because you can't afford to snowboard for 7 hours with less than $15. </em>
x=6 Hours
<span>2(x+4)^2 - (3y+5)^3
at x=-3 and y=-1
2(-3+4)^2 - ((3*-1)+5)^3
2 (1)^2 - (2)^3
2 - 8
(-6)</span>
