statistics what is meant by re-expressing or transforming data? what is the purpose of re expressing or transforming data

Mathematics

1 answer:

Archy [21]1 year ago

3 0

Re-expressing data means making the facts more appropriate for evaluation by our methods.

We can not use a linear version until the connection among the 2 variables is linear. Often re-expression (transformation) can save the day, straightening bent relationships in order that we are able to suit and use a easy linear version.

• Two easy approaches to re-specific facts are with logarithms and reciprocals.

• Re-expressions may be visible in regular life— all and sundry does it.

We can re-specific gas performance as gallons in step with hundred miles (a reciprocal) and get rid of the bend in the authentic scatterplot.

Therefore, re-expressing data means making the facts more appropriate for evaluation by our methods.

Learn more about re-expressing data here:

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a gardener has 322 tulip bulbs she wants to plant rows of 15 bulbs how many bulbs can be planted how many bulbs will she have le

Elden [556K]

Answer:315 bulbs planted and 7 left over

Step-by-step explanation:322/15 = 21.44

Roughly around 21 rows.

21 x 15 = 315 bulbs planted

322 - 315 = 7 bulbs left over

3 0

3 years ago

Six stand-up comics, A, B, C, D, E, and F, are to perform on a single evening at a comedy club. The order of performance is

kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

$P(F=4th)=1/6$

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

$P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36$

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

$P(F, D, B, A, C, E)=1/720$

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

$P(C=6th\,or\, E=6th)=2/6=1/3$