Answer:
No
Step-by-step explanation:
<u>Step 1: Set x to 5 and check</u>
<u />


So... 5 is not a solution
Answer: No
This is for the first one :) sorry I don’t have time to do the other two, but this will help with the other ones
In this case or scenario,
the double-angle identity that should be used is the one for cosine. <span>
In totality, we shall need the following three trigonometric
identities to end up with the equality:
<span>1. cos (2a) = cos² (a) - sin² (a)
2. sin² (a) + cos² (a) = 1
<span>3. tan² (a) + 1 = sec²
(a)
<span>Using identities 1 and 2 on the left-hand side of the
equation, we get the following:</span>
1 + cos (2a) = 1 + cos² (a) - sin² (a) = 2 cos² (a) </span></span></span>
<span>
<span>Recalling that cos² (a) = 1 / sec² (a) and applying identity
3, we find the following:</span>
2 cos² (a) = 2 / sec² (a) = 2 / (1 + tan² (a)) </span>
Therefore giving us:
<span>2 cos² (a) = 2 / (1 +
tan² (a))</span>
Answer: 26
Step-by-step explanation: From the remainder theorem ,
If P (x) = 2x⁴ ⁻ x³ + 2x² ⁻ 6. is divided by ( x - 2 ).
It means that if P(x) is divided by (x - 2 ) and leaves a Remainder, it implies that x - 2 is not a factor of P(x) , but if it leaves no remainder, it means x-2 is a factor of P(x).
Therefore , to find the remainder, find the zero of x - 2, and substitutes for the value in P(x) to know the remainder
x - 2 = 0
x = 2
Now put this in P(x)
P(x) = 2(2)⁴ - (2)³ + 2(2)² - 6
= 2(16) -8 + 2(4) -6
= 32 -8 +8 -6
=26
Therefore the remainder when P(x) is divided by x -2
=26
Note: Since the division of P(x) by x - 2 leaves a remainder, it means that
x - 2 ≠ a factor of P(x)