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Vinvika [58]
4 years ago
12

What's the lateral area of the square pyramid 8m 8m 22 m

Mathematics
2 answers:
sasho [114]4 years ago
7 0
I think the anwsers 1408
kompoz [17]4 years ago
5 0

The formula for finding the lateral area of any square base pyramid is:

A=a\sqrt{a^2+4h^2}

Where "a" is the base edge or the edge of the square and "h" is the height of the pyramid.

In our case, "a"=8 meters and "h"=22 meters

\therefore A=8\sqrt{8^2+4(22)^2} \approx357.77 squared meters

Thus, the lateral area of the given square pyramid is 357.77 squared meters.

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Is 5 a solution to -3x=15
viva [34]

Answer:

No

Step-by-step explanation:

<u>Step 1:  Set x to 5 and check</u>

<u />-3x = 15

-3(5) = 15

-15 \neq  15

So... 5 is not a solution

Answer:  No

3 0
3 years ago
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This is for the first one :) sorry I don’t have time to do the other two, but this will help with the other ones

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Which double-angle or half-angle identity would you use to verify that 1+cos2a=2/1+tan2a?
juin [17]

In this case or scenario, the double-angle identity that should be used is the one for cosine. <span>

In totality, we shall need the following three trigonometric identities to end up with the equality: 

<span>1. cos (2a) = cos² (a) - sin² (a)
2. sin² (a) + cos² (a) = 1 
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<span>Using identities 1 and 2 on the left-hand side of the equation, we get the following:</span>

1 + cos (2a) = 1 + cos² (a) - sin² (a) = 2 cos² (a) </span></span></span>

<span>

<span>Recalling that cos² (a) = 1 / sec² (a) and applying identity 3, we find the following:</span>

2 cos² (a) = 2 / sec² (a) = 2 / (1 + tan² (a)) </span>

 

Therefore giving us:

<span>2 cos² (a) = 2 / (1 + tan² (a))</span>

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4 years ago
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P(x)=2x^4-x^3+2x^2-6. What is the remainder when P(x) is divided by (x-2)?
aleksandr82 [10.1K]

Answer: 26

Step-by-step explanation: From the remainder theorem ,

If P (x) = 2x⁴ ⁻ x³ + 2x² ⁻ 6. is divided by ( x - 2 ).

It means that if P(x) is divided by (x - 2 ) and leaves a Remainder, it implies that x - 2 is not a factor of P(x) , but if it leaves no remainder, it means x-2 is a factor of P(x).

Therefore , to find the remainder, find the zero of x - 2, and substitutes for the value in P(x)  to know the remainder

x - 2 = 0

x = 2

Now put this in P(x)

P(x) = 2(2)⁴ - (2)³ + 2(2)² - 6

= 2(16) -8 + 2(4) -6

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=26

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