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Murljashka [212]
3 years ago
13

P(x)=2x^4-x^3+2x^2-6. What is the remainder when P(x) is divided by (x-2)?

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Answer: 26

Step-by-step explanation: From the remainder theorem ,

If P (x) = 2x⁴ ⁻ x³ + 2x² ⁻ 6. is divided by ( x - 2 ).

It means that if P(x) is divided by (x - 2 ) and leaves a Remainder, it implies that x - 2 is not a factor of P(x) , but if it leaves no remainder, it means x-2 is a factor of P(x).

Therefore , to find the remainder, find the zero of x - 2, and substitutes for the value in P(x)  to know the remainder

x - 2 = 0

x = 2

Now put this in P(x)

P(x) = 2(2)⁴ - (2)³ + 2(2)² - 6

= 2(16) -8 + 2(4) -6

= 32 -8 +8 -6

=26

Therefore the remainder when P(x) is divided by x -2

=26

Note: Since the division of P(x) by x - 2 leaves a remainder, it means that

x - 2 ≠ a factor of P(x)

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3 years ago
What is 1/3 of 57 current size?
ludmilkaskok [199]

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3 years ago
In any given season, a soccer team plays 65% of their games at home. When the team plays at home, they win 83% of their games. W
kodGreya [7K]

Answer:

29.9%

Step-by-step explanation:

We have that 65% of the games are at home, therefore 35% (100 - 65) are away from home.

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Also away from home they win 26% of the games, which means that 74% (100 -26) lose them.

We are asked that if the team does not win the game, find the probability that the game was played at home.

Then the favorable cases would be that he has played at home and that he has lost, that is, 65% (home games) and 17% (lost at home), the probability would be:

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Now, the probability that he loses, either at home or away from home, would be the sum of the previous probability plus when he loses away, which would be 35% of the away games, the 74% who are the losers, is say:

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Therefore the probability would be:

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8 0
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Answer:

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