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Kobotan [32]
2 years ago
7

Fitness tests check to see how physically fit you are. How can a fitness assessment help you to improve your fitness? What area

of your fitness do you want to improve?
Physics
1 answer:
mixer [17]2 years ago
4 0

Fitness assessment can help us to improve our fitness simply by setting goals to improve their healthy fitness

However, fitness testing is an effective strategy to monitor and assess our fitness levels in general as it helps us to understand how healthy they are by learning about the five components of fitness .

<h3>What is physical fitness?</h3>

This simply refers to a state of an individual being physically healthy.

In order words, it is a condition of being physically fit and healthy.

So therefore, fitness assessment can help you to improve our fitness simply by setting goals to improve their health-related fitness

Learn more about fitness:

brainly.com/question/24364238

#SPJ1

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A railroad car moving at a speed of 3.49 m/s overtakes, collides, and couples with two coupled railroad cars moving in the same
Mandarinka [93]

Answer:

Explanation:

Using conservation law of momentum

let m₁ = mass of the railroad, initial u₁ = 3.49 m/s

let m₂ = mass of one of the coupled car,  u₂= 1.28m/s

let m₃ = mass of the second car u₃ = 1.28 m/s

m₁u₁ + m₂u₂ + m₃u₃ = v ( m₁ + m₂ + m₃)

since the masses are the same

m₁ = m₂ = m₃

m ( 3.49 + 1.28 + 1.28) = 3m v

6.05 m = 3 mv

v = 6.05 m / 3m = 2.0167 m/s

b) kinetic energy lost = energy before collision - energy after collision

= (0.5m₁u₁² + 0.5 ( m₁+m₂) u₂² - 0.5 ( m₁ + m₂ + m₃) v

= (6.58365 + 1.7712) - 6.5951 = 1.76J  

7 0
3 years ago
For an object to be classified as a ____, it must meet certain definite criteria: It must be massive enough to pull itself into
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a planet

Explanation:

a planet is one which exerts these properties and therefore is the answer

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4 years ago
A space probe is directly between two moons of a planet. If it is twice as far from moon A as it is from moon B, but the net for
Dennis_Churaev [7]

Answer:

c. Moon A is four times as massive as moon B

Explanation:

Let's assume the:

  • mass of the object = m\,kilogram
  • mass of the moon A = M_A\,kilogram
  • mass of the moon B = M_B\,kilogram
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According to the given condition the object is twice as far from moon A as it is from moon B

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<u>As we know, gravitational force of attraction is given by:</u>

F=G\frac{m_1.m_2}{r^2}

<em>According to the condition</em>

Force on m due toM_B=Force on m due toM_A

G\frac{m.M_A}{(2r)^2} =G\frac{m.M_B}{(r)^2}

\frac{M_A}{4r^2} =\frac{M_B}{r^2}

M_A=4M_B

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it would be c.

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