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dem82 [27]
3 years ago
10

The charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electro

n.If Millikan was measuring the charge on an oil droplet with 10 negatively charged electrons on it, what charge would he have measured on the droplet?
Physics
1 answer:
shusha [124]3 years ago
3 0

Answer:

1.6\times 10^{-18} C  

Explanation:

The fundamental charge of a single electron is 1.6\times 10^{-19} C.

If there are 10 excess electrons, the net charge that would be measured should be 10 times the fundamental charge of a single electron:

Q=nq_e\\Q= 10\times 1.6\times 10^{-19} C\\Q= 1.6 \times 10^{-18} C

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dezoksy [38]
F = ma
100n = m(5m/s^2)
100/5 = 20

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3. Automobile companies often test the safety of cars by putting them through crash tests to observe the integrity of the passen
Nadya [2.5K]

Answer:

Time taken for car to stop = 0.89 seconds (Approx.)

Explanation:

Given:

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Computation:

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Change in momentum of car = -16,500

Time taken for car to stop = I Change in momentum of car I / Impact force

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Time taken for car to stop = 0.89 seconds (Approx.)

6 0
3 years ago
Scientist A believes she has discovered a new procedure that is better than a procedure currently in use by physicians. She test
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B

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2 years ago
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The length of a cylindrical axon is 8 cm and its radius of 8μm,and the thickness of the membrane is 0.01μm,dielectric constant (
GuDViN [60]

Answer:

9.965 nF

Explanation:

The capacitance of the axon C = εA/d where ε = dielectric constant = 24.78 × 10⁻¹² F/m, A = surface area of axon = 2πrL where r = radius of axon = 8 μm = 8 × 10⁻⁶ m and L = length of axon = 8 cm = 8 × 10⁻² m and d = thickness of membrane = 0.01 μm = 0.01 × 10⁻⁶ m

So, C = εA/d

C = ε2πrL/d

Substituting the of the values variables into the equation, we have

C = ε2πrL/d

C =  24.78 × 10⁻¹² F/m × 2π × 8 × 10⁻⁶ m × 8 × 10⁻² m/0.01 × 10⁻⁶ m

C =  9964.63 × 10⁻²⁰ Fm/0.01 × 10⁻⁶ m

C =  996463 × 10⁻¹⁴ F

C = 9.96463 × 10⁻⁹ F

C = 9.96463 nF

C ≅ 9.965 nF

6 0
3 years ago
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
GuDViN [60]

Answer:

Q = 12540  J

Explanation:

It is given that,

Mass of water, m = 50 mL = 50 g

It is heated from 0 degrees Celsius to 60 degrees Celsius.

We need to find the energy required to heat the water. The formula use to find it as follows :

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Put all the values,

Q=50\times 4.18\times (60-0)\\Q=12540\ J

So, 12540 J of energy is used to heat the water.

7 0
2 years ago
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