All categories

4 years ago

Can someone plss helpp?? :)

Physics

1 answer:

katrin [286]4 years ago

8 0

C. The canoe's path will be a diagonal line from northeast to southwest.

Explanation:

We can solve this problem by using vector addition rules.

In fact, we know that:

- The velocity of the canoe has a component in the south direction, due to the velocity of the river which points towards south

- The canoe itself is trying to go from the eastern shore towards the western shore --> this means that the canoe has also a component of the velocity in the west direction

This means that the resultant velocity of the canoe must be in a direction intermediate between the directions of its two components: therefore, in the southwest direction.

Therefore, this means that

C. The canoe's path will be a diagonal line from northeast to southwest.

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

You might be interested in

1. Since sleep is so important, we might wonder why people so often fail to get a sufficient amount

ziro4ka [17]

Answer: 9/10

Explanation:

because it's really important and makes you energetic

8 0

3 years ago

Which of the events below does NOT happen during the G1 phase of the cell cycle

aleksandr82 [10.1K]

Answer:

Could you please add the events

Explanation:

if not I could give a brief explanation of what happens in the phase and you could just eliminate?

6 0

3 years ago

A man walks 30m to the west, then 5m to the east in 45 seconds. What is the average velocity?

solong [7]

1.28m/s the velocity is found by distance/time.

8 0

4 years ago

Read 2 more answers

Uphill escape ramps are sometimes provided to the side of steep downhill highways for trucks with overheated brakes. For a simpl

o-na [289]

Answer:

404.4 m

Explanation:

Converting the initial speed from km/h to m/s then

$140\times \frac {1000m}{3600s}=38.88888889 m/s \approx 38.89 m/s$

The acceleration is resolved as shown in the figure hence

deceleration of the truck along the inclined plane will be

$a=-g sin \theta$ where g is acceleration due to gravity

Substituting g with $9.81 m/s^{2}$ then

$a=-9.81 m/s^{2} sin 11^{\circ}=-1.871836245\approx -1.87 m/s^{2}$

Using kinematic equation

$v^{2}=u^{2}+2as$ and making s the subject then

$s=\frac {v^{2}-u^{2}}{2a}$ where v and u are final and initial velocities respectively

Substituting 0 for v, 38.89 m/s for u and $-1.87 m/s^{2}$ then

$s=\frac {0^{2}-38.89^{2}}{2\times -1.87}=404.3936096 m\approx 404.4 m$

3 0

3 years ago

A 3000 kg deck is cantilevered over a beam as shown. It is attached to the house at the other end. Find the force of the beam.

Afina-wow [57]

The beam is acting as the pivot and the weight of the deck acts through its center its gravity, at the midpoint of the deck.
Center of gravity at: (16 + 4)/2 = 10 ft

Converting 4 ft to meters: 1.22 m
Converting 10 ft to meters: 3.05

F x 1.22 = 3.05 x 3000 x 9.81
F = 73,600 N

4 0

4 years ago