Answer A, climbing vines. Thigmotropism is growth in response to mechanical contact.
As long as the graph is a straight line they both will give same answer. Edit: In the case of errors,I think the most fitting slope line is more accurate method,because taking average is same as drawing a line from initial to final point of the line and taking its slope.
Hope it helps
Answer:
- <em>In both cases the tension in the rope is </em><u>equal to 500N</u>
Explanation:
It may be that in the case of the <em>tree</em>, the result is more intuitive, because you can think that there is only one force. But this is misleading.
To find the <em>tension in the rope</em>, you should draw a free body diagram. By doing so, you would find that the rope is static because there are two opposite forces. Assuming, for simplicity, that the rope is horizontal, a force of 500N is pulling to one direction (let's say to the right) and a force of 500N is pulling to the opposite direction (to the left). Else, the rope would not be static.
That analysys is the same for the<em> rope tied to the tree</em> ( the tree is pulling with 500N, such as the man, but in opposite direction) and when the rope is pulled by <em>two men</em> on opposite ends, each with<em> forces of 500N.</em>
Hence, the tension is the same and equal to 500N.
Answer:
I_{total} = 10 M R²
Explanation:
The concept of moment of inertia in rotational motion is equivalent to the concept of inertial mass for linear motion. The moment of inertia is defined
I = ∫ r² dm
For body with high symmetry it is tabulated, in these we can simulate them by a solid disk, with moment of inertia for an axis that stops at its center
I = ½ M R²
As you hear they ask for the moment of energy with respect to an axis parallel to the axis of the disk, we can use the theorem of parallel axes
I = 
+ M D²
Where I_{cm} is the moment of inertia of the disk, M is the total mass of the system and D is the distance from the center of mass to the new axis
Let's apply these considerations to our problem
The moment of inertia of the four discs is
I_{cm} = I
I_{cm} = ½ M R²
For distance D, let's use the Pythagorean Theorem. As they indicate that the coins are touched the length of the square is L = 2R, the distance from any spine to the center of the block is
D² = (R² + R²)
D² = R² 2
Let's calculate the moment of inertia of a disk with respect to the axis that passes through the center of the square
I = ½ M R2 + M R² 2
I = 5/2 M R²
This is the moment of inertia of a disc as we have four discs and the moment of inertia is a scalar is additive, so
= 4 I
I_{total} = 4 5/2 M R²
I_{total} = 10 M R²
Gravitational acceleration (Ga) is inversely proportional to k / Distance^2
so Ga * Distance^2 = K
On the surface of Earth acceleration due to gravity is about 9.8m/s^2 with an average distance to the earths core of about 6371 km (Wolfram alpha).
So k = 9.8 * 6371^2
I'm presuming that your distance of 116 is km
As
Ga = k / distance^2
Ga = ((9.8 * 6371^2) / (6371 + 116)^2 ) = 397778481.8 / 42081169
= 9.45 m/s^2 to 2sf
