Answer:
When the drill hits oil, some of the oil rises from the ground high into the air. This immediate release of oil is known as a "gusher." Once a reservoir has been located, pumps are used to extract the oil.
Answer: 502 Joules
Explanation:
To calculate the mass of water, we use the equation:

Density of water = 1 g/mL
Volume of water = 40.0 mL
Putting values in above equation, we get:

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

The equation used to calculate heat released or absorbed follows:

q = heat absorbed by water
= mass of water = 40.0 g
= final temperature of water = 20.0°C
= initial temperature of water = 17.0°C
= specific heat of water= 4.186 J/g°C
Putting values in equation 1, we get:
![q=40.0\times 4.186\times (20.0-17.0)]](https://tex.z-dn.net/?f=q%3D40.0%5Ctimes%204.186%5Ctimes%20%2820.0-17.0%29%5D)

Hence, the joules of heat were re-leased by the lead is 502
Answer:
624510100
Explanation:
Doing a conversion factor:
![0,0006245101[km]*\frac{1000[m]}{1 km} *\frac{1x10^{9} nanometer}{1 m} =624510100 [nanometer]](https://tex.z-dn.net/?f=0%2C0006245101%5Bkm%5D%2A%5Cfrac%7B1000%5Bm%5D%7D%7B1%20km%7D%20%2A%5Cfrac%7B1x10%5E%7B9%7D%20nanometer%7D%7B1%20m%7D%20%3D624510100%20%5Bnanometer%5D)
Answer:
Anhydrous sodium carbonate is stable to heat and does not decompose even when it is heated to redness. This is because sodium carbonate salt on heating with acids react to release carbon dioxide.
Explanation:
Let us take the volume of block is x.
Since, the block is floating this means that it is in equilibrium. Formula to calculate net force will be as follows.

Also, buoyancy force
= (volume submerged in water × density of water) + (volume in oil × density of oil)
=
=
g
As, W = V × density of graphite × g
It is given that density of graphite is
or 2160
.
So, W = 2160 V g
= (0.592 V \rho + 408 V) g - 2160 V g = 0
= 1752
= 2959.46
or 2.959
is the density of oil.
It is given that mass of flask is 124.8 g.
Mass of 35.3
oil =
104.7 g
Hence, in second weighing total mass will be calculated as follows.
(124.8 + 104.7) g
= 229.27 g
Thus, we can conclude that in the second weighing mass is 229.27 g.