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AURORKA [14]
3 years ago
14

According to the big bang theory, the universe—all of the stars, planets, and galaxies everywhere—began as a very small, dense m

ass. This mass expanded suddenly in an incredibly hot explosion-like event, and it has spent the last 13.7 billion years rapidly expanding and cooling.
In 1964, which of the following space technologies provided scientists with the best evidence that the universe was created in the big bang?
A.
a lunar module
B.
a Mars rover
C.
a radio telescope
D.
a weather satellite
Chemistry
1 answer:
Colt1911 [192]3 years ago
3 0
Lunar module or radio telescope
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F a balloon containing 1000 L of gas 50 Celsius and 101.3kpa rises to an altitude where pressure is 27.5 kpa amd the temperature
inna [77]

Answer:

V₂ =  3227.46 L

Explanation:

Given data:

Initial volume of gas = 1000 L

Initial temperature = 50°C  (50 +273 = 323 K)

Initial pressure = 101.3 KPa

Final pressure = 27.5 KPa

Final temperature = 10°C  (10 +273 = 283 K)

Final volume = ?

Solution:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 101.3 KPa × 1000 L × 283 K / 323 K × 27.5 KPa

V₂ = 28667900 KPa .L. K /   8882.5 K.KPa

V₂ =  3227.46 L

7 0
3 years ago
Name an element or elements in the periodic table that you would expect to be chemically similar to potassium.
Rina8888 [55]
Potassium (K) is in Group I of the periodic table, and elements in the same column (period) are similar. Sodium (Na), or lithium (Li) are similar.
6 0
3 years ago
Can anyone help me with this?
Scrat [10]

Explanation:

c2H5

|

cH3 _ c _ c H2 _ c H3

|

c2H5

cH3

|

cH3_ cH _ cH_ cH2_ cH3

|

cH3

5 0
3 years ago
How many moles of copper are there in 6.93 g of copper sample<br>pls be quick​
Alex_Xolod [135]
  • Molar mass of copper=63.5g/mol
  • Given mass=6.93g

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{6.93}{63.5}

\\ \sf\longmapsto No\:of\:moles=0.109\approx 1.11moles

7 0
2 years ago
Read 2 more answers
What should you do during a titration when you notice the indicator start to indicate the approach of the equilibrium point? Add
Leni [432]

B. Add the second reactant slower.

6 0
3 years ago
Read 2 more answers
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