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3 years ago

Which of the following pure compounds will exhibit hydrogen bonding?

Chemistry

1 answer:

zimovet [89]3 years ago

4 0

Explanation:

For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.

For example, $CH_{3}CH_{2}OH$ , $CH_{3}NH_{2}$ and $NH_{3}$ all these compounds contain an electronegative atom attached to hydrogen atom.

Therefore, these pure compounds will exhibit hydrogen bonding.

Thus, we can conclude that out of the given options $CH_{3}CH_{2}OH$ , $CH_{3}NH_{2}$ and $NH_{3}$ are the pure compounds which will exhibit hydrogen bonding.

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Alkenes on reacting with ozone results in the formation of ozonide which undergo reductive cleavage in presence of dimethyl sulfide to form carbonyl compounds (aldehyde or ketone). Whereas in presence of hydrogen peroxide it undergoes oxidative cleavage to form carboxylic acids or ketones.

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The reaction is as shown in the image.

The reaction of A with m-CPBA (meta-perchlorobenzoic acid) followed by aqueous acid $H_3O^{+}$ is shown in the image.

m-CPBA (meta-perchlorobenzoic acid) is a peracid and forms epoxides on reacting with alkenes.

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