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vagabundo [1.1K]
3 years ago
5

Which of the following pure compounds will exhibit hydrogen bonding?

Chemistry
1 answer:
zimovet [89]3 years ago
4 0

Explanation:

For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.

For example, CH_{3}CH_{2}OH, CH_{3}NH_{2} and NH_{3} all these compounds contain an electronegative atom attached to hydrogen atom.

Therefore, these pure compounds will exhibit hydrogen bonding.

Thus, we can conclude that out of the given options CH_{3}CH_{2}OH, CH_{3}NH_{2} and NH_{3} are the pure compounds which will exhibit hydrogen bonding.

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If 5 grams of hydrogen reacted with 40 games of oxygen to form water, how much of water would be formed?
GREYUIT [131]
2H₂ + O₂ = 2H₂O

n(H₂)=m(H₂)/M(H₂)
n(H₂)=5g/2.0g/mol=2.5 mol

n(O₂)=m(O₂)/M(O₂)
n(O₂)=40g/32.0g/mol=1.25 mol

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3 0
2 years ago
What is the mass of Ca(NO3)2?
Solnce55 [7]

Ca=40.07841 ,Nitrogen=14.006722 ,Oxygen15.99943
molar mass= (1xMW of Ca)+(2xMWof N)+(6x MW of oxygen)
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7 0
2 years ago
How many liters of 0.1107 M KCI contain 15.00 g of KCI (FW 74.6 g/mol)? O0.02227 L O 0.5502 L 01661 L O 1.816 L 18.16 L
Greeley [361]

Answer:

1,816 L

Explanation:

Molar concentration or molarity is a way to express the concentration of a chemical in terms of moles of substances per liter of solution.

To obtain the liters of this solution you must convert moles/L to g/L with formula weight (FW), thus:

0,1107 mol of KCl / L × (74,6 g / mol) = 8,258 g of KCl / L.

It means that in one liter you have 8,258 g of KCl. Thus, 15,00 g of KCl are contained in:

15,00 g × (1 L / 8,258 g) = 1,816 L

I hope it helps!

3 0
3 years ago
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