Which of the following pure compounds will exhibit hydrogen bonding?

Chemistry

1 answer:

zimovet [89]3 years ago

4 0

Explanation:

For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.

For example, $CH_{3}CH_{2}OH$ , $CH_{3}NH_{2}$ and $NH_{3}$ all these compounds contain an electronegative atom attached to hydrogen atom.

Therefore, these pure compounds will exhibit hydrogen bonding.

Thus, we can conclude that out of the given options $CH_{3}CH_{2}OH$ , $CH_{3}NH_{2}$ and $NH_{3}$ are the pure compounds which will exhibit hydrogen bonding.

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The mass of an object is 1,000 g. It has a volume of 100 mL. What is the density of the object? D= mass/volume

maxonik [38]

Answer:

10 g/ml

Explanation:

divide mass by volume means divide 1000 by 100 and your answer will be 10

4 0

3 years ago

Write a balanced half-reaction for the reduction of permanganate ion mno−4 to solid manganese dioxide mno2 in acidic aqueous sol

Svetlanka [38]

The half-reaction includes either the reduction or the oxidation reaction of the redox reactions. In acidic solution permanganate ion will react with hydrogen ion to yield manganese ion and water.

<h3>What are Redox reactions?</h3>

Redox or oxidation-reduction reactions are the chemical reactions in which the oxidation and the reduction of the chemical species occur simultaneously.

Permanganate (VII) ion is a strong oxidizing agent and gets easily reduced to manganese ion in presence of the hydrogen ion in an acidic solution.

The balanced half-reaction for reduction is shown as,

$\rm MnO_{4}^{-} \; (aq)+ 8H^{+} \; (aq)+ 5e^{-} \rightarrow Mn^{2+} \; (aq)+ 4H_{2}O \; (l)$