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vladimir1956 [14]
1 year ago
5

he seven problems, which were announced in 2000, are the Riemann hypothesis, P versus NP problem, Birch and Swinnerton-Dyer conj

ecture, Hodge conjecture, Navier-Stokes equation, Yang-Mills theory, and Poincaré conjecture.
Mathematics
1 answer:
solniwko [45]1 year ago
3 0

Answer:

Huh these are the world's on solved problems

Step-by-step explanation:

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A red token is worth twice as much as an orange token. An orange token is worth 5 less a yellow token. A yellow token is worth 1
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Answer:

Step-by-step explanation:

Let r represent red token,

Let o represent orange token,

Let y represent yellow token

Let g represent green token,

A red token is worth twice as much as an orange token. It means that

r = 2o

An orange token is worth 5 less a yellow token. It means that

o = y - 5

A yellow token is worth 15 less than a green token. It means that

y = g - 15

A green token is worth half as much as a blue token. It means that

g = b/2

a blue token is worth B. Therefore, the worth of a yellow token in terms of B would be

Substituting g = B/2 into y = g - 5, it becomes

y = B/2 - 15

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Step-by-step explanation:

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