Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Answer: AC= 10 cm and CE= 5 cm
Step-by-step explanation:
In the given picture, Δ ADE is a right triangle
∴ By Pythagoras theorem,

Since triangles ABC and ADE are similar and corresponding sides of similar triangles are proportional therefore,

Now, AE=AC+CE
⇒CE=AE-AC
⇒CE=15-10=5 cm
Answer:
25500
Step-by-step explanation:
You can simplify the fraction to get 2/5. If you convert this into a decimal you will get 0.4, so D is your answer.