Factor over the complex numbers, if possible: x² + 2xyi - y2 What is the answer?
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Answer:
2
Step-by-step explanation:
we start simplifying by removing the parenthesis
Multiply the exponents inside the the parenthesis
3^4 * 2^4
Now we apply exponential property
a^m * a^n = a^ (m+n)
3^4 * 3^-3 = 3^ (4-3) = 3^1
3 or 3^1 are same
3^1 at the top and bottom so we cancel it out
\frac{2^4}{2^3}
we apply log property . a^m / a^n = a^m-n
Now subtract the exponents
2^(4-3) = 2^1 = 2