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2 years ago

Give an in-depth answer on how to expand polynomials

1 answer:

5 0

To expand a polynomial, multiply its factors by using the distributive property and then combine all like terms.

<h3>How to illustrate the information?</h3>

It should be noted that a polynomial is an expression which is composed of variables, constants and exponents, which are combined using the mathematical operations such as addition, subtraction, multiplication and division

A polynomial is expanded if there's no variable appears within parentheses and all like terms have been combined.

To expand a polynomial, multiply its factors by using the distributive property or perform the indicated operations. Then combine all like terms.

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Number one please...

deff fn [24]

where is number 1 i dont see it

5 0

4 years ago

Debbie has $460 in a savings account that earns 8% annually. If the interest is not compounded, how much interest will she earn

mario62 [17]

She earned $184 in interest.

$644 in all.

Here's why:

The formula is interest = principal x rate x time.

i = 460 x 8% x 5 or i = 460 x 0.08 x 5.

PEMDAS

460(0.08) = 36.8

i = 36.8 x 5

36.8 x 5 = 184

i = $184

To find them in all, add the original amount she deposited with the interest.

460 + 184 = 644

In all: $644

5 0

3 years ago

(sqrt3-sqrt3i)^4

Ludmilka [50]

The increasing order of the complex numbers is (√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.

<h3>Absolute values of the complex numbers</h3>

The absolute values of the complex numbers are determined as follows;

(sqrt3-sqrt3i)^4 = (√3 - √3i)⁴

$|z| = \sqrt{(\sqrt{3} )^2 + (\sqrt{3 }\times1 )^2} } \\\\|z| = \sqrt{6}$

(-1+sqrt3i)^12 = (-1 + √3i)¹²

$|z| = \sqrt{(-1)^2 + (\sqrt{3)^2} } \\\\|z| = \sqrt{4} \\\\|z| = 2$

(sqrt 3-i)^6 = (√3 - i)⁶

$|z| = \sqrt{(\sqrt{3})^2 + (-1)^2 } \\\\|z| = \sqrt{4} \\\\|z| = 2$

(sqrt2-sqrt2i)^8 = (√2 - √2i)⁸

$|z| = \sqrt{(\sqrt{2} )^2 + (\sqrt{2})^2 } \\\\|z| = 2$

(sqrt2-i)^6 = (√2 - i)⁶

$|z| = \sqrt{(\sqrt{2})^2 + (-1)^2} } \\\\|z| = \sqrt{3}$

Increasing order of the complex numbers;

(√2 - i)⁶ < (√2 - √2i)⁸ = (√3 - i)⁶ = (-1 + √3i)¹² < (√3 - √3i)⁴.

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3 0

3 years ago

Number two please <br> ASAP

miv72 [106K]

The solutions for $-5 +2x^{2} = -6x$ is option 3. $x= \frac{-6 \pm \sqrt{36-4 (2)(-5)}}{4} .$

Step-by-step explanation:

Step 1:

First, we must bring the equation to the form of $ax^{2} +bx +c =0.$

So $-5 +2x^{2} = -6x$ becomes $2x^{2} +6x-5=0.$

The value of a is the coefficient of the $x^{2}$ term, the value of b is the coefficient of x term and c is the coefficient of the constant term.