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Anna71 [15]
2 years ago
5

Which of the following identifies the individuals in the set?

Mathematics
1 answer:
MaRussiya [10]2 years ago
5 0

The individuals of a set are the various data or variable of a data set.

The study's participants or study subjects are referred to as individuals. The trait of the person being measured or observed is known as a variable. For instance, if we were to do a research on climbers of Mount Everest, the participants would be the real climbers who succeeded in reaching the summit.

A categorical variable places each individual in to a category such as male or female.

A quantitative variable has numerical values that measure some characteristic of each individual, such as height in centimeter or salary in dollars.

The problem deals with the concept of types of variables. We use the definition of variables to identify/determine the type variable from the known information.

The individuals in the data set are vehicles or cars.

The given information is related to the different types of cars and its model, and specifications. Hence, the vehicles or cars are individuals in the data set.

To learn more about individuals in a dataset:

brainly.com/question/3744191

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x= 2/6

Step-by-step explanation:

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add 1 to both sides

divide 6 to both sides to isolate x

x = 2/6

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The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran
VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, X = "Comprehensive strength of concrete". We have information that X is normally distributed with a mean of 2500 psi and a standard deviation of  50 psi (or a variance of 2500 psi). In other words, X \sim N(2500, 2500).

We want to know the probability of the mean of X or \bar{X} that falls in the interval [2499;2510]. From inference theory we know that :

\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)

Now we can find the probability as follows:

P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )

Where Z \sim N(0,1), then:

P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798

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4 years ago
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