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1 year ago

14

Alesha went to the movies. A popcorn is $3 more than a soda. She purchased 1 popcorn and 2 sodas. She spent $21. How much is a p

opcorn?

1 answer:

Blizzard [7]1 year ago

8 0

Answer: a popcorn is $9

Step-by-step explanation:

soda is $6

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2d + 3 when d =8 <br> im stuck on this question on a paper due monday!

xeze [42]

Answer:

19

Step-by-step explanation:

2d + 3

d = 8

2(8) + 3

multiply 2 and 8

16 + 3

add 16 and 3

= 19

4 0

2 years ago

Someone please help me will give brainliest!!!!!

ololo11 [35]

I believe the fastest way to solve this problem is to take any two of the given points and to find the slope and y-intercept of the line connecting those two points.

Let's choose the 2 given points (-3,16) and (-1,12).
Going from the first point to the second, the increase in x is 2 and the increase in y is actually a decrease: -4. Thus, the slope of the line connecting these two points is m = -4/2, or m = -2.

Now use the slope-intercept formula to find the y-intercept, b.

One point on the line is (-3,16), and the slope is m = -2.

Thus, the slope-intercept formula y = mx + b becomes 16 = -2(-3) + b.
Here, b comes out to 10.

So now we have the slope and the y-intercept. Write the equation:

y = mx + b becomes y=-2x+10. Which of the four given answer choices is the correct one?

3 0

2 years ago

Express each number as a single-digit integer times a power of 10.<br> 24,755,183,009,522

jek_recluse [69]

2 to the 12th power should be correct

7 0

3 years ago

Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.

Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the following condition must be followed:

Either (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

for the equation ax² + bx + c = 0

thus,

the roots are

$x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}$

or

$x = \frac{6\pm\sqrt{36-12}}{2}$

or

$x = \frac{6+\sqrt{24}}{2}$ and, x = $x = \frac{6-\sqrt{24}}{2}$

or

$x = \frac{6+2\sqrt{6}}{2}$ and, x = $x = \frac{6-2\sqrt{6}}{2}$

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

$x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}$

or

$x = \frac{4\pm\sqrt{16+56}}{4}$

or

$x = \frac{4+\sqrt{72}}{4}$ and, x = $x = \frac{4-\sqrt{72}}{4}$

or

$x = \frac{4+\sqrt{2^2\times3^2\times2}}{2}$ and, x = $x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}$

or

$x = \frac{4+(2\times3)\sqrt{2}}{2}$ and, x = $x = \frac{4-(2\times3)\sqrt{2}}{4}$

or

$x = \frac{2+3\sqrt{2}}{2}$ and, $x = \frac{2-(3)\sqrt{2}}{2}$

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; $x = \frac{2+3\sqrt{2}}{2}$ ; $x = \frac{2-(3)\sqrt{2}}{2}$

7 0

2 years ago

Given that a function, g, has a domain of -20 sxs 5 and a range of 5 s 39 s 45 and that g(0) = -2 and g(-9) = 6, select the stat

luda_lava [24]

Answer:

option (B) and (D)

Step-by-step explanation:

It's just basic of domain and range just check out the domain and range you can get your answer .

Only option (B) and (D) satisfy in the given range and domain

8 0

3 years ago