32.9%, is the percentage of compound left after 6.07 minutes.
We utilize the equation A(t) = A0e-kt for decomposition, where A0 is the beginning amount of the decomposed substance at time t = 0, k is the decay constant, t is the passing of time, and A(t) is the amount at the end of time t.
The original amount, [A0], multiplied by 100 to get [A(t)], or A/A0*100, is the fraction of the decomposed molecule that is still present after time t:
A = A0e-kt
Divide both sides by A0, k = 0.00299, and A/A0 = e-0.00299t.
A/Ao is equal to e-0.00299*372, where
t = 6.2 min*(60 sec/ 1 min)
= 372 sec.
A/A0 = .3288 = 32.9%,
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