Ask question

Ask question

All categories

xxTIMURxx [149]

3 years ago

10

A bird flies at an average velocity of 3.60 m/s for 18.4 s. How far does it travel? (unit=m)

1 answer:

jarptica [38.1K]3 years ago

5 0

First, you have to write what you know:

V = 3.60 m/s
D = ?
T = 18.4 s

Next, you plug everything into this formula:

V = D/T
3.60 m/s = ?/18.4 s

Then, you multiply 3.60 m/s and 18.4 s

D = 66.24 m

You might be interested in

Under specific circumstances, waves will bend around obstacles. This type of bending is called

BartSMP [9]

That type of bending is called "diffraction" of waves.

6 0

3 years ago

As a football player moves in a straight line [displacement (3.00 mm)i^i^ - (6.50 mm)j^j^], an opponent exerts a constant force

Brilliant_brown [7]

Answer:

Work done, $W=(0.378i-1.092j)\ J$

Explanation:

Displacement,

$d=(3i-6.5j)\ mm\\\\d=(0.003i-0.0065j)\ m$

Force, $F=(126i+168j)\ N$

Work done by the opponent do on the football player is given by :

$W=F{\cdot} d\\\\W=(126i+168j){\cdot} (0.003i-0.0065j)\ m\\\\W=(0.378i-1.092j)\ J$

So, the work done by the opponent do on the football player is $(0.378i-1.092j)\ J$ .

4 0

3 years ago

Read 2 more answers

A block weighing 3.7 kg is suspended from the ceiling of a truck trailer by a hanging bungee cord. The cord has a cross-sectiona

sweet [91]

Answer:

$Y = 2.27 \times 10^{10} N/m^2$

Explanation:

Natural length of the string is given as

$L_o = 43 cm$

length of the string while block is hanging on it

$L = 53 cm$

extension in length is given as

$\Delta L = 10 cm$

now we have strain in the string is given as

$strain = \frac{\Delta L}{L}$

$strain = \frac{{10 cm}{43 cm}$

$strain = 0.23$

similarly we will have cross-sectional area of the string is given as

$A = 40 \times 10^{-6} m^2$

now the stress in the string is given as

$Stress = \frac{T}{A}$

$Stress = \frac{mg}{A}$

$Stress = \frac{3.7 \times 9.81}{40 \times 10^{-6}}$

$stress = 9.07 \times 10^5 N/m^2$

Now Young's Modulus is given as

$Y = \frac{stress}{strain}$

$Y = \frac{9.07 \times 10^5}{40\times 10^{-6}}$

$Y = 2.27 \times 10^{10} N/m^2$

5 0

3 years ago

How can you increase the torque you are putting on a lever, without exerting any more force?

Mariana [72]

Answer:

See below

Explanation:

Torgue = f * distance basically ...so if you want to increase torque with same f then the distance ( lever arm) must be increased

4 0

3 years ago

When are scalars used?

Shkiper50 [21]

When you have to wait some

7 0

3 years ago